c++ - 从子构造函数（模板）访问父成员

Question

所以我有一些简单的问题/结构：

 class Class1 {
   public:
      Class1() {};
      ~Class1() {};
   protected:
      std::string name;
 }

 class Class2 : public Class1
 {
   public:
     Class2() : number(id_generator++) {
       name = "My-name"; // (1) want to access field inherited from Parent
   };

   private:
      const unsigned int number;
      static unsigned int id_generator;
  }

编译器抱怨 (1): 'name' was not declared in this scope。怎么了？它看起来很简单，但我看不到它。

EDIT1：只是我意识到错误实际上只在这里发音（这里链接到代码）：

#include <string>

template<int dim>
class Class1 {
   public:
      Class1() {};
     ~Class1() {};
   protected:
      std::string name;
 };

template<int dim>
class Class2 : public Class1<dim>
{
   public:
     Class2() : number(id_generator++) {
       name = "My-name"; // (1) want to access field inherited from Parent
     };

   private:
     const unsigned int number;
     static unsigned int id_generator;
};

int main() {}

所以显然我把模板弄乱了。对不起，没有把它写在第一位。

Answer 1

In a template, for unqualified names that refer to members inherited from a base class, you should use the explicit syntax by dereferencing this:

 Class2() : number(id_generator++) {
     this->name = "My-name"; // (1) want to access field inherited from Parent
 //  ^^^^^^
 };

Or, alternatively, you could qualify the name this way:

 Class2() : number(id_generator++) {
     Class1<dim>::name = "My-name";
 //  ^^^^^^^^^^^^^
 };

Otherwise, the compiler will lookup name in the global namespace during the first phase of name lookup and, if not found, will issue an error.

Answer 2

除了缺少分号，代码很好。

唯一可能的解释是Class1，如编译器所见，实际上并没有该name成员。你有多个班级Class1吗？您是否有声明的头文件的多个副本Class1？您是否有可能在运行编译器之前忘记保存文件？