1

所以我正在学习如何使用 Selenium 进行网络自动化——我正在尝试编写一个脚本，将我的美国运通余额返回到我的控制台。第一步其实就是登录成功了……

看来我单击登录按钮的操作引发了找不到元素的错误，即使我在使用 firebug 时可以看到它。

这是我的代码：

from selenium import webdriver

driver = webdriver.Firefox()

baseurl = "https://www.americanexpress.com/canada/"
username = "myusername"
password = "mypassword"

xpaths = { 'usernameField' : "//input[@id='UserID']",
           'passwordField' : "//input[@id='Password']",
           'submitButton' :   "//input[@id='loginButton']"
         }

driver.get(baseurl)

driver.find_element_by_xpath(xpaths['usernameField']).clear()

driver.find_element_by_xpath(xpaths['usernameField']).send_keys(username)

driver.find_element_by_xpath(xpaths['passwordField']).clear()

driver.find_element_by_xpath(xpaths['passwordField']).send_keys(password)

driver.find_element_by_xpath(xpaths['submitButton']).click()

这是我得到的控制台错误消息，浏览器已经填写了我的登录详细信息，但还没有点击登录按钮：

Traceback (most recent call last):
  File "get_balance.py", line 29, in <module>
    driver.find_element_by_xpath(xpaths['submitButton']).click()
  File "/Library/Python/2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 232, in find_element_by_xpath
    return self.find_element(by=By.XPATH, value=xpath)
  File "/Library/Python/2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 664, in find_element
    {'using': by, 'value': value})['value']
  File "/Library/Python/2.7/site-packages/selenium/webdriver/remote/webdriver.py", line 175, in execute
    self.error_handler.check_response(response)
  File "/Library/Python/2.7/site-packages/selenium/webdriver/remote/errorhandler.py", line 166, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: {"method":"xpath","selector":"//input[@id='loginButton']"}
Stacktrace:
    at FirefoxDriver.prototype.findElementInternal_ (file:///var/folders/mx/dbnsd72j05zd4k2cls4cvmf00000gn/T/tmpKQDaey/extensions/fxdriver@googlecode.com/components/driver-component.js:10271)
    at FirefoxDriver.prototype.findElement (file:///var/folders/mx/dbnsd72j05zd4k2cls4cvmf00000gn/T/tmpKQDaey/extensions/fxdriver@googlecode.com/components/driver-component.js:10280)
    at DelayedCommand.prototype.executeInternal_/h (file:///var/folders/mx/dbnsd72j05zd4k2cls4cvmf00000gn/T/tmpKQDaey/extensions/fxdriver@googlecode.com/components/command-processor.js:12274)
    at DelayedCommand.prototype.executeInternal_ (file:///var/folders/mx/dbnsd72j05zd4k2cls4cvmf00000gn/T/tmpKQDaey/extensions/fxdriver@googlecode.com/components/command-processor.js:12279)
    at DelayedCommand.prototype.execute/< (file:///var/folders/mx/dbnsd72j05zd4k2cls4cvmf00000gn/T/tmpKQDaey/extensions/fxdriver@googlecode.com/components/command-processor.js:12221)

有什么想法吗？非常感谢任何建议/帮助，谢谢！

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1 回答 1

2

这是一个a元素，而不是input：

<a tabindex="0" href="#" id="loginButton" title="Login securely">
    <span></span>
    Log In
</a>

将您的 xpath 更改为：//a[@id="loginButton"].

除此之外，对于id属性还有一个find_element_by_id()方法：

driver.find_element_by_id("loginButton").click()

此外，如果您想将元素定位器与实际的“动作”代码分开，您可以通过以下方式对其进行配置（作为示例，留下一个 xpath 表达式）：

from selenium.webdriver.common.by import By

locators = { 
    'usernameField': (By.ID, "UserID"),
    'passwordField': (By.XPATH, "//input[@id='Password']"),
    'submitButton': (By.ID, "loginButton")
}

然后，您的“操作”代码将使用find_element()：

username = driver.find_element(*locators['usernameField'])
username.clear()
username.send_keys(username)

password = driver.find_element(*locators['passwordField'])
password.clear()
password.send_keys(password)

login_button = driver.find_element(*locators['submitButton'])
login_button.click()
于 2015-03-09T02:38:40.003 回答