我很难理解如何正确使用 bindParam();
我一直在关注以下 URL 的详细信息：http: //php.net/manual/en/pdo.prepared-statements.php，其中显示以下内容作为他们的示例之一：
<?php $stmt = $dbh->prepare("INSERT INTO REGISTRY (name, value) VALUES (?, ?)"); $stmt->bindParam(1, $name); $stmt->bindParam(2, $value); // insert one row $name = 'one'; $value = 1; $stmt->execute(); // insert another row with different values $name = 'two'; $value = 2; $stmt->execute(); ?>
这个例子显然是不完整的，但是，它显示了足够的细节，我应该能够重现相同的结果。
我已将下面的代码从我的主程序中提取出来，并将其放入它自己的文件中，看看我是否可以隔离问题，到目前为止，它已经解决了。我复制了输入数据的片段，以重新创建与真实数据相同的条件，好吧，我做对了，因为我遇到了同样的错误。
我一直收到错误消息：Call to undefined method mysqli_stmt::bindparam()这让我相信出了点问题stmt。所以，我放了一些调试代码来看看里面是什么stmt。它似乎是一个对象，因此，它已定义，在此之前没有抛出任何 SQL 错误提示 SQL 语法错误，一切都连接，并且似乎运行正常，并且在我看来，该对象已定义，但是，分钟它会使用它，它是未定义的。
我不知所措，因为我尽可能地遵循了这个例子。它似乎bindParam()在设置时使用了引用，所以我提前创建了变量，所以它有一些可以使用的东西。
我对此有一些不明白的地方，并且文档解释得不够充分，我无法理解。
以下是我正在使用的测试脚本，它是完整的文件，减去了一些明显的东西。
<?php
$servername = "localhost";
$username = "-----";
$password = "--------";
$dbname = "-----";
$EN["Data"]["Episode"][1]["id"] = "1";
$EN["Data"]["Episode"][1]["seasonid"] = "14";
$EN["Data"]["Episode"][1]["seriesid"] = "143";
$EN["Data"]["Episode"][1]["SeasonNumber"] = "1";
$EN["Data"]["Episode"][1]["EpisodeName"] = "1";
$EN["Data"]["Episode"][2]["id"] = "2";
$EN["Data"]["Episode"][2]["seasonid"] = "14";
$EN["Data"]["Episode"][2]["seriesid"] = "143";
$EN["Data"]["Episode"][2]["SeasonNumber"] = "1";
$EN["Data"]["Episode"][2]["EpisodeName"] = "2";
echo "<pre>";
print_r($EN);
echo "</pre>";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if (! $conn->set_charset("utf8mb4")) {
die("Error loading character set utf8: " . $conn->error);
}
$stmt = $conn->prepare( "INSERT INTO TVEpisodes
(id, seasonid, seriesid, SeasonNumber, EpisodeName)
VALUES (?, ?, ?, ?, ?)" );
if ($stmt == FALSE) { /*<--- didn't fail here. */
echo "Error: " . $sql . "<br>" . $conn->error;
exit(); // should not happen at this point, mabye...
}
echo "<pre>";
var_dump($stmt); /*<--- both show I have data.*/
print_r($stmt);
echo "</pre>";
$episode_id = " ";
$episode_seasonid = " ";
$episode_seriesid = " ";
$episode_SeasonNumber = " ";
$episode_EpisodeName = " ";
$stmt->bindParam(1, $episode_id); /*<------ fails here.*/
echo "<pre>";
var_dump($stmt);
print_r($stmt);
echo "</pre>";
$stmt->bindParam(2, $episode_seasonid);
$stmt->bindParam(3, $episode_seriesid);
$stmt->bindParam(4, $episode_SeasonNumber);
$stmt->bindParam(5, $episode_EpisodeName);
foreach ($EN["Data"]["Episode"] as &$episode) {
echo "<pre>->>>";
print_r($episode);
echo "<<<<- </pre>";
$episode_id = $episode["id"];
$episode_seasonid = $episode["seasonid"];
$episode_seriesid = $episode["seriesid"];
$episode_SeasonNumber = $episode["SeasonNumber"];
$episode_EpisodeName = $episode["EpisodeName"];
if ($stmt->execute() != TRUE) {
echo "Error: " . $sql . "<br>" . $conn->error;
exit(); // should not happen at this point, mabye...
}
}
?>
这是显示正在吐出的值的输出页面。
Array ( [Data] => Array ( [Episode] => Array ( [1] => Array ( [id] => 1 [seasonid] => 14 [seriesid] => 143 [SeasonNumber] => 1 [EpisodeName] => 1 ) [2] => Array ( [id] => 2 [seasonid] => 14 [seriesid] => 143 [SeasonNumber] => 1 [EpisodeName] => 2 ) ) ) ) object(mysqli_stmt)[2] public 'affected_rows' => null public 'insert_id' => null public 'num_rows' => null public 'param_count' => null public 'field_count' => null public 'errno' => null public 'error' => null public 'error_list' => null public 'sqlstate' => null public 'id' => null mysqli_stmt Object ( [affected_rows] => 0 [insert_id] => 0 [num_rows] => 0 [param_count] => 5 [field_count] => 0 [errno] => 0 [error] => [error_list] => Array ( ) [sqlstate] => 00000 [id] => 1 ) ( ! ) Fatal error: Call to undefined method mysqli_stmt::bindparam() in /home/-long-path-/test.php on line 45