1

好的，我们有一个简单的 udf，它接受一个 XML 整数列表并返回一个表：

CREATE FUNCTION [dbo].[udfParseXmlListOfInt]
(
    @ItemListXml XML (dbo.xsdListOfInteger)
)
RETURNS TABLE 
AS
RETURN
(   --- parses the XML and returns it as an int table ---
    SELECT ListItems.ID.value('.','INT') AS KeyValue 
      FROM @ItemListXml.nodes('//list/item') AS ListItems(ID)
)

在存储过程中，我们使用此 UDF 创建一个临时表

INSERT INTO @JobTable 
    (JobNumber, JobSchedID, JobBatID, StoreID, CustID, CustDivID, BatchStartDate, BatchEndDate, UnavailableFrom)
SELECT JOB.JobNumber, 
       JOB.JobSchedID,
       ISNULL(JOB.JobBatID,0), 
       STO.StoreID, 
       STO.CustID, 
       ISNULL(STO.CustDivID,0),
       AVL.StartDate, 
       AVL.EndDate,
       ISNULL(AVL.StartDate, DATEADD(day, -8, GETDATE()))
  FROM dbo.udfParseXmlListOfInt(@JobNumberList) TMP
       INNER JOIN dbo.JobSchedule       JOB ON (JOB.JobNumber = TMP.KeyValue)
       INNER JOIN dbo.Store             STO ON (STO.StoreID = JOB.StoreID)
       INNER JOIN dbo.JobSchedEvent     EVT ON (EVT.JobSchedID = JOB.JobSchedID AND EVT.IsPrimary = 1)
       LEFT OUTER JOIN dbo.Availability AVL ON (AVL.AvailTypID = 5 AND AVL.RowID = JOB.JobBatID)
 ORDER BY JOB.JobSchedID;

对于 SQL2005 中 10 个 JobNumber 的简单列表，它在不到 1 秒内返回，在 2008 年，这个运行与在 7 分钟内返回完全相同的数据。这是在具有更多内存的速度更快的机器上。有任何想法吗？

如果我更改 SP 来执行此操作，则性能将与 2005 版本相当。

DECLARE @JobNumbers TABLE
(
        JobNumber       INT     NOT NULL 
    );

    INSERT INTO @JobNumbers
        (JobNumber)
    SELECT * from dbo.udfParseXmlListOfInt(@JobNumberList);


INSERT INTO @JobTable 
    (JobNumber, JobSchedID, JobBatID, StoreID, CustID, CustDivID, BatchStartDate, BatchEndDate, UnavailableFrom)
SELECT JOB.JobNumber, 
       JOB.JobSchedID,
       ISNULL(JOB.JobBatID,0), 
       STO.StoreID, 
       STO.CustID, 
       ISNULL(STO.CustDivID,0),
       AVL.StartDate, 
       AVL.EndDate,
       ISNULL(AVL.StartDate, DATEADD(day, -8, GETDATE()))
  FROM @JobNumbers TMP
           INNER JOIN dbo.JobSchedule       JOB ON (JOB.JobNumber = TMP.JobNumber)
       INNER JOIN dbo.Store             STO ON (STO.StoreID = JOB.StoreID)
       INNER JOIN dbo.JobSchedEvent     EVT ON (EVT.JobSchedID = JOB.JobSchedID AND EVT.IsPrimary = 1)
       LEFT OUTER JOIN dbo.Availability AVL ON (AVL.AvailTypID = 5 AND AVL.RowID = JOB.JobBatID)
 ORDER BY JOB.JobSchedID;
4

1 回答 1

2

验证服务器是否具有相同的索引。

还要检查统计信息是否是最新的：

SELECT 
    object_name = Object_Name(ind.object_id),
    IndexName = ind.name,
    StatisticsDate = STATS_DATE(ind.object_id, ind.index_id)
FROM SYS.INDEXES ind
order by STATS_DATE(ind.object_id, ind.index_id) desc

如需更多帮助，请发布查询执行计划之间的差异 ( set showplan_text on)

于 2010-05-18T21:36:21.620 回答