我正在为一个 I18N 项目做出贡献,并且有人调用将我们的 *.resx 文件序列化为 JSON 对象(无论出于何种原因)。
我想知道的是:
- 有没有办法获取给定 *.resx 文件的所有有效键的列表,以便我们可以使用 HttpContext.GetGlobalResourceObject 来获取令牌?
- 如果这不起作用,有没有人想出一个聪明的解决方案呢?
我正在为一个 I18N 项目做出贡献,并且有人调用将我们的 *.resx 文件序列化为 JSON 对象(无论出于何种原因)。
我想知道的是:
Sub ReadRessourceFile()
''#Requires Assembly System.Windows.Forms
Dim rsxr As System.Resources.ResXResourceReader = New System.Resources.ResXResourceReader("items.resx")
''# Iterate through the resources and display the contents to the console.
Dim d As System.Collections.DictionaryEntry
For Each d In rsxr
Console.WriteLine(d.Key.ToString() + ":" + ControlChars.Tab + d.Value.ToString())
Next d
''#Close the reader.
rsxr.Close()
End Sub
然后您需要将其添加到可序列化字典中,然后您可以使用 System.Web.Extensions.dll 将其序列化为 JSON
Public Class JSONHelper
Public Shared Function Serialize(Of T)(ByVal obj As T) As String
Dim JSONserializer As System.Web.Script.Serialization.JavaScriptSerializer = New System.Web.Script.Serialization.JavaScriptSerializer()
Return JSONserializer.Serialize(obj)
End Function
Public Shared Function Deserialize(Of T)(ByVal json As String) As T
Dim obj As T = Activator.CreateInstance(Of T)()
Dim JSONserializer As System.Web.Script.Serialization.JavaScriptSerializer = New System.Web.Script.Serialization.JavaScriptSerializer()
obj = JSONserializer.Deserialize(Of T)(json)
Return obj
End Function
End Class
编辑:C#:
public void ReadRessourceFile()
{
//Requires Assembly System.Windows.Forms '
System.Resources.ResXResourceReader rsxr = new System.Resources.ResXResourceReader("items.resx");
// Iterate through the resources and display the contents to the console. '
System.Collections.DictionaryEntry d = default(System.Collections.DictionaryEntry);
foreach (DictionaryEntry d_loopVariable in rsxr) {
d = d_loopVariable;
Console.WriteLine(d.Key.ToString() + ":" + ControlChars.Tab + d.Value.ToString());
}
//Close the reader. '
rsxr.Close();
}
JSON 助手:
public class JSONHelper
{
public static string Serialize<T>(T obj)
{
System.Web.Script.Serialization.JavaScriptSerializer JSONserializer = new System.Web.Script.Serialization.JavaScriptSerializer();
return JSONserializer.Serialize(obj);
}
public static T Deserialize<T>(string json)
{
T obj = Activator.CreateInstance<T>();
System.Web.Script.Serialization.JavaScriptSerializer JSONserializer = new System.Web.Script.Serialization.JavaScriptSerializer();
obj = JSONserializer.Deserialize<T>(json);
return obj;
}
}