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我有一个要求，我必须通过 HTTPS 使用休息服务，并且必须在运行时获取 URL。为了完成同样的任务，我将 REST 'url' 设置为出站属性，并尝试使用 MEL 获取它

#[message.outboundProperties.'url'

当尝试按照我上面所说的做时，我收到下面提到的编译时错误 

org.springframework.beans.MethodInvocationException: Property 'protocol' threw exception; nested exception is java.lang.IllegalArgumentException: Address '#[message.outboundProperties.'url']' for protocol 'http' should start with http://

我做错什么了吗？还是有除此之外实现此要求的最佳方法吗？

	<https:outbound-endpoint exchange-pattern="request-response"
							  method="GET" doc:name="HTTPs with Auth header" address="#[message.outboundProperties.'url']" connector-ref="HTTP_HTTPS"/>

    <https:connector name="HTTP_HTTPS" cookieSpec="netscape" validateConnections="true" sendBufferSize="0" receiveBufferSize="0" receiveBacklog="0" clientSoTimeout="10000" serverSoTimeout="10000" socketSoLinger="0" doc:name="HTTP-HTTPS">
        <https:tls-key-store path="#[message.outboundProperties.'Storepath']" keyPassword="#[message.outboundProperties.'storepassword']" storePassword="#[message.outboundProperties.'storepassword']"/>
        <https:tls-server path="#[message.outboundProperties.'Storepath']" storePassword="#[message.outboundProperties.'storepassword']"/>
    </https:connector>

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1 回答 1

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Http 组件需要一个静态的“HTTP://”作为 URL 的开头，因此下面的工作

<http:outbound-endpoint exchange-pattern="request-response" method="GET" address="http://#[message.outboundProperties.'url'] " doc:name="HTTP"/>
于 2015-01-20T13:27:03.157 回答