运行以下代码：
#include <iostream>
#include <boost/numeric/odeint.hpp>
using namespace std;
using namespace boost::numeric::odeint;
class CSystem
{
private:
int counter=0;
public:
void operator() ( const double &x , double &dxdt , const double t)
{
double mat_A=-1;
double mat_B=1;
dxdt=mat_A*x+mat_B*1;
cout<<"counter: "<<counter<<endl;
counter++; // seems it does not apply to the rest of the iterations appropriately
}
void solve()
{
double x;
x = 0.0;
typedef runge_kutta_dopri5<double> stepper_type;
std::function<void(const double &,const double)> my_observer = [&](const double &x,const double t){/* do nothing*/};
integrate_adaptive(make_controlled(1E-10,1E-10,stepper_type()),
*this,x,0.0,3.0,0.1,my_observer);
}
};
int main()
{
CSystem sys;
sys.solve();
return 0;
}
我希望counter从 0 开始计数并cout生成以下输出：
0
1
2
3
4
5
6
7
8
9
10
11
...
当我得到别的东西时：
counter: 0
counter: 0
counter: 1
counter: 2
counter: 3
counter: 4
counter: 5
counter: 0
counter: 1
counter: 2
counter: 3
counter: 4
counter: 5
counter: 0
counter: 1
counter: 2
counter: 3
...
什么是重置计数器？看起来很像！
解决这个问题的正确方法是什么？我宁愿避免使用外部对象。