我可能需要一些帮助来弄清楚如何提供下面的过程。我需要编写一个单色 BMP 文件。下面的代码(来自:如何在 windows C++ 中将单色图像另存为 bmp ?)看起来能够做到这一点。我现在坚持如何将 astd::bitset
或最好boost::dynamic_bitset
转换为这种byte*
格式。到目前为止,我所有的尝试都失败了,我无法将 8x8 棋盘格模式写入 BMP。proc 创建了 BMP,它可以被 Photoshop 读取,但内容是一团糟。因此,感谢您提出任何解决此问题的建议!
Save1BppImage(byte* ImageData, const char* filename, long w, long h){
int bitmap_dx = w; // Width of image
int bitmap_dy = h; // Height of Image
// create file
std::ofstream file(filename, std::ios::binary | std::ios::trunc);
if(!file) return;
// save bitmap file headers
BITMAPFILEHEADER fileHeader;
BITMAPINFOHEADER * infoHeader;
infoHeader = (BITMAPINFOHEADER*) malloc(sizeof(BITMAPINFOHEADER) );
RGBQUAD bl = {0,0,0,0}; //black color
RGBQUAD wh = {0xff,0xff,0xff,0xff}; // white color
fileHeader.bfType = 0x4d42;
fileHeader.bfSize = 0;
fileHeader.bfReserved1 = 0;
fileHeader.bfReserved2 = 0;
fileHeader.bfOffBits = sizeof(BITMAPFILEHEADER) + (sizeof(BITMAPINFOHEADER));
infoHeader->biSize = (sizeof(BITMAPINFOHEADER) );
infoHeader->biWidth = bitmap_dx;
infoHeader->biHeight = bitmap_dy;
infoHeader->biPlanes = 1;
infoHeader->biBitCount = 1;
infoHeader->biCompression = BI_RGB; //no compression needed
infoHeader->biSizeImage = 0;
infoHeader->biXPelsPerMeter = 0;
infoHeader->biYPelsPerMeter = 0;
infoHeader->biClrUsed = 2;
infoHeader->biClrImportant = 2;
file.write((char*)&fileHeader, sizeof(fileHeader)); //write bitmapfileheader
file.write((char*)infoHeader, (sizeof(BITMAPINFOHEADER) )); //write bitmapinfoheader
file.write((char*)&bl,sizeof(bl)); //write RGBQUAD for black
file.write((char*)&wh,sizeof(wh)); //write RGBQUAD for white
int bytes = (w/8) * h ; //for example for 32X64 image = (32/8)bytes X 64 = 256;
file.write((const char*)ImageData, bytes);
file.close();
}
-编辑-
我的一个天真的方法是这样的
byte test[64];
for(unsigned int i=0; i<64; ++i)
if(i % 2)
test[i] = 0;
else
test[i] = 1;
Save1BppImage(test, "C:/bitmap.bmp", 8, 8);