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我是一个被困在coldfusionland的PHP研究员，我需要一些帮助，我提前谢谢你。

我正在尝试根据欠款、每年的付款次数来设置付款时间表。

我在组件中有一个方法：

<!--- declare method vars --->
    <cfset begBal = 1200>
    <cfset curBal = "1000">
    <cfset pymntsPerYear = 12>
    <cfset pymntAmnt = 0>
    <cfset pymntsLeft = "">
    <cfset prettyPymntsPerYear = "">
    <cfset movingBal = 0>
    <!--- set numerical value for frequency --->
    <cfswitch expression=#pymntsPerYear#>
        <cfcase value="52">
            <cfset pymntsPerYear = "52">
            <cfset prettyPymntsPerYear = "Weekly">
        </cfcase>
        <cfcase value="12">
            <cfset pymntsPerYear = "12">
            <cfset prettyPymntsPerYear = "Monthly">
        </cfcase>
        <cfcase value="24">
            <cfset pymntsPerYear = "24">
            <cfset prettyPymntsPerYear = "Twice Monthly">
        </cfcase>
        <cfcase value="26">
            <cfset pymntsPerYear = "26">
            <cfset prettyPymntsPerYear = "Every 2 Weeks">
        </cfcase>
        <cfcase value="1">
            <cfset pymntsPerYear = "1">
            <cfset prettyPymntsPerYear = "Quarterly">
        </cfcase>
    </cfswitch>
    <!--- set balance, if we have payments that have already been made, we wouldnt want to start
        the new payment schedule at the original balance --->

    <!--- loop through and do the math for the new schedule --->
    <cfset pymntAmnt = begBal / pymntsPerYear>
    <cfloop from="1" to="#pymntsPerYear#" index="i">
        <cfset movingBal += movingBal - (movingBal - pymntAmnt)>
        PAYMENT NUMBER: #i#  #dollarFormat(pymntAmnt)#, balance = #dollarFormat(movingBal)#<br>
    </cfloop>
        <cfoutput>The new schedule will be #pymntsPerYear# #prettyPymntsPerYear# Payments @ #dollarFormat(pymntAmnt)#</cfoutput>

但是输出是出乎意料的。我试图在每次付款后获得新的余额，但它似乎向后工作，即：（100,200,300）不是我所期望的，即：（300,200,100,0）

查看输出

付款号码：1 $100.00，余额 = $100.00
付款号码：2 $100.00，余额 = $200.00
付款号码：3 $100.00，余额 = $300.00
付款号码：4 $100.00，余额 = $400.00
付款号码：5 $100.00，余额 = $560.00
付款，余额= $ 600.00
付款编号：7 $ 100.00，余额= $ 700.00
付款号：8 $ 100.00，余额= $ 800.00
付款号：9 $ 100.00，余额= $ 900.00
付款号：10 $ 100.00，余额= $ 1,000.00 付款
编号：11 $ 100.00，余额= $ 1,100.00
号码：12 $100.00，余额 = $1,200.00
新计划将是 12 个月付款 @ $100.00

如何使其“desc”并以 Balance = 0 结束？

4

1 回答 1

3

也许像这样？

<!--- declare method vars --->
<cfset begBal = 1200>
<cfset curBal = "1000">
<cfset pymntsPerYear = 12>
<cfset pymntAmnt = 0>
<cfset pymntsLeft = "">
<cfset prettyPymntsPerYear = "">
<cfset movingBal = begBal>
<!--- set numerical value for frequency --->
<cfswitch expression=#pymntsPerYear#>
    <cfcase value="52">
        <cfset pymntsPerYear = "52">
        <cfset prettyPymntsPerYear = "Weekly">
    </cfcase>
    <cfcase value="12">
        <cfset pymntsPerYear = "12">
        <cfset prettyPymntsPerYear = "Monthly">
    </cfcase>
    <cfcase value="24">
        <cfset pymntsPerYear = "24">
        <cfset prettyPymntsPerYear = "Twice Monthly">
    </cfcase>
    <cfcase value="26">
        <cfset pymntsPerYear = "26">
        <cfset prettyPymntsPerYear = "Every 2 Weeks">
    </cfcase>
    <cfcase value="1">
        <cfset pymntsPerYear = "1">
        <cfset prettyPymntsPerYear = "Quarterly">
    </cfcase>
</cfswitch>
<!--- set balance, if we have payments that have already been made, we wouldnt want to start
    the new payment schedule at the original balance --->

<!--- loop through and do the math for the new schedule --->
<cfset pymntAmnt = begBal / pymntsPerYear>
<cfoutput>
<cfloop from="1" to="#pymntsPerYear#" index="i" >
    <cfset movingBal -= movingBal - (movingBal - pymntAmnt)>
    PAYMENT NUMBER: #i#  #dollarFormat(pymntAmnt)#, balance = #dollarFormat(movingBal)#<br>
</cfloop>
The new schedule will be #pymntsPerYear# #prettyPymntsPerYear# Payments @ #dollarFormat(pymntAmnt)#
</cfoutput>
于 2014-12-10T16:47:18.677 回答