3

给定这样的 UTC 时间字符串:

2005-11-01T00:00:00-04:00

使用 Crystal Reports 公式将其转换为 DateTime 的最佳方法是什么?

我最好的解决方案发布在下面。

我希望外面有人可以用单线把我吹走...

4

4 回答 4

3

我可以建议对 jons911 的回答进行简化:

CDateTime(CDate(Left({@UTCString}, 10)), CTime(Mid({@UTCString}, 12, 8)));  

这样做的好处是该公式适用于 UTC 0 之前的时区(例如 +01:00)。它当然依赖于 UTC 字符串是格式正确的 ISO 8601 字符串。

于 2008-11-13T23:30:10.603 回答
2

干得好:

CDateTime(CDate(Split({?UTCDateString}, "T")[1]) , CTime(Split(Split({?UTCDateString}, "T")[2], "-")[1]))
于 2008-11-07T03:29:49.847 回答
1

这是我最好的解决方案,并附有评论:

//assume a date stored as a string in this format:
//2005-11-01T00:00:00-04:00
//return a DateTime value
StringVar fieldValue;
StringVar datePortion;
StringVar timePortion;
NumberVar yearPortion;
NumberVar monthPortion;
NumberVar dayPortion;
NumberVar hourPortion;
NumberVar minutePortion;
NumberVar secondPortion;

//store the field locally so i can easily copy-paste into another formula
//(where the field name will be different)
//Crystal formulas do not use a powerful language.
fieldValue := {PACT.ReferralDate};

//break up the date & time parts.
//ignore the -04:00 offset part of the time.
datePortion := Split (fieldValue,"T")[1];
timePortion := Split(Split (fieldValue,"T")[2],"-")[1];

yearPortion := ToNumber(Split(datePortion,"-")[1]);
monthPortion := ToNumber(Split(datePortion,"-")[2]);
dayPortion := ToNumber(Split(datePortion,"-")[3]);

hourPortion := ToNumber(Split(timePortion,":")[1]);
minutePortion := ToNumber(Split(timePortion,":")[2]);
secondPortion := ToNumber(Split(timePortion,":")[3]);

//finally, return the result as a date-time
DateTime(yearPortion,monthPortion,dayPortion,hourPortion,minutePortion,secondPortion);
于 2008-11-07T03:17:14.723 回答
0
StringVar fieldValue;
StringVar datePortion;
StringVar timePortion;
NumberVar yearPortion;
NumberVar monthPortion;
NumberVar dayPortion;
NumberVar hourPortion;
NumberVar minutePortion;
NumberVar secondPortion;
datetimevar dtlimite;

fieldValue := {dtsecretaria.Data_limite};

datePortion := Split (fieldValue,"T")[1];
timePortion := Split(Split (fieldValue,"T")[2],"-")[1];

yearPortion := ToNumber(Split(datePortion,"-")[1]);
monthPortion := ToNumber(Split(datePortion,"-")[2]);
dayPortion := ToNumber(Split(datePortion,"-")[3]);

hourPortion := ToNumber(Split(timePortion,":")[1]);
minutePortion := ToNumber(Split(timePortion,":")[2]);
secondPortion := ToNumber(Split(timePortion,":")[3]);

dtlimite := DateTime(yearPortion,monthPortion,dayPortion,hourPortion,minutePortion,secondPortion);


if dtlimite > CurrentDateTime then

Color(255,0,0)

else

Color(255,255,0)



error of nError in formula  <Back_Color>. \n'\r'\nA string is required here."
于 2009-05-15T15:56:05.723 回答