我想从我的画廊拍一张照片,我想给它一个“id”来使用我的 android 应用程序。
问问题
124 次
2 回答
1
甚至在按钮单击时,调用以下代码....
Intent intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(intent, GET_IMAGE);
并且,在活动结果上,编写以下代码:
if (requestCode == GET_IMAGE) {
targetUri = data.getData();
imageView.setImageURI(targetUri);
}
在哪里,private static final int GET_IMAGE = 2;
于 2012-07-23T09:15:56.537 回答
0
你可以试试下面的代码
btnChoosePhoto.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Intent i = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Images.Media.INTERNAL_CONTENT_URI);
startActivityForResult(i, 1);
}
});
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if(resultCode == RESULT_OK && requestCode == 1 ) {
final Uri selectedImage = data.getData();
try {
bitmap = Media.getBitmap(getContentResolver(),selectedImage);
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 90, bytes);
//path = selectedImage.getEncodedPath();
// create new file to write the encrypted bytes of image in file
File f = new File(Environment.getExternalStorageDirectory()
+ File.separator
+ filename);
f.createNewFile();
FileOutputStream fo = new FileOutputStream(f);
fo.write(bytes.toByteArray());
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
imageView.setImageBitmap(bitmap);
}
}
于 2012-07-23T09:19:34.957 回答