我需要将数值转换为罗马数字,但遇到了一些麻烦。当我测试我的代码并且用户输入一个数字时,代码会将其转换为罗马数字,但之后我无法再次出现提示;在放置不正确的整数后它会重新提示,但在正确的整数之后不会。我不知道如何做到这一点,以便用户可以继续转换值,直到他们选择 -1 退出。以下是我迄今为止提出的。
import java.util.Scanner;
public class arabicToRoman {
static String a = "";
public static void main (String[] args){
Scanner input = new Scanner(System.in);
System.out.println("Enter a number between 1 and 3999 (-1 to quit): ");
while (!input.hasNext("-1")) {
String a = input.next();
try {
Integer number = Integer.parseInt(a);
if ((number <= 3999) && (number > 0)) {
System.out.println(arabicToRoman(number));
} else if (number > 3999) {
System.out.println("Error: number must be between 1 and 3999");
} else if (number == 0) {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
} else {
System.out.println("Error: The Romans did not have a way to represent negative numbers or zero.");
}
} catch (NumberFormatException e) {
System.out.println("You did not enter a number!");
}
}
}
public static String arabicToRoman(int arabic) {
while (arabic >= 1000){
a += "M";
arabic -= 1000;
}
while (arabic >= 900){
a += "CM";
arabic -= 900;
}
while (arabic >= 500){
a += "D";
arabic -= 500;
}
while (arabic >= 400){
a += "CD";
arabic -= 400;
}
while (arabic >= 100){
a += "C";
arabic -= 100;
}
while (arabic >= 90){
a += "XC";
arabic -= 90;
}
while (arabic >= 50){
a += "L";
arabic -= 50;
}
while (arabic >= 40){
a += "XL";
arabic -= 40;
}
while (arabic >= 10){
a += "X";
arabic -= 10;
}
while (arabic >= 9){
a += "IX";
arabic -= 10;
}
while (arabic >= 5){
a += "V";
arabic -= 5;
}
while (arabic >= 4){
a += "IV";
arabic -= 4;
}
while (arabic >= 1){
a += "I";
arabic -= 1;
}
return a;
}
}
输入后,似乎显示结果,但之后没有提示,但用户可以输入其他内容,它会读取它;如果它是另一个数字,则结果将添加到先前的结果中。