17

在 C# 中使用 XML 序列化时，我使用如下代码：

public MyObject LoadData()
{
    XmlSerializer xmlSerializer = new XmlSerializer(typeof(MyObject));
    using (TextReader reader = new StreamReader(settingsFileName))
    {
        return (MyObject)xmlSerializer.Deserialize(reader);
    }
}

（以及类似的反序列化代码）。

它需要铸造并且不是很好。有没有办法直接在 .NET Framework 中使用带有序列化的泛型？也就是说要写这样的东西：

public MyObject LoadData()
{
    // Generics here.
    XmlSerializer<MyObject> xmlSerializer = new XmlSerializer();
    using (TextReader reader = new StreamReader(settingsFileName))
    {
        // No casts nevermore.
        return xmlSerializer.Deserialize(reader);
    }
}
4

5 回答 5

29

除了@Oded，您还可以使方法通用：

public T ConvertXml<T>(string xml)
{
    var serializer = new XmlSerializer(typeof(T));
    return (T)serializer.Deserialize(new StringReader(xml));
}

这样你就不需要使整个类通用，你可以像这样使用它：

var result = ConvertXml<MyObject>(source);
于 2010-04-19T19:30:22.790 回答
13

使您的序列化类/方法通用：

public T LoadData<T>()
{
    XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));
    using (TextReader reader = new StreamReader(settingsFileName))
    {
        return (T)xmlSerializer.Deserialize(reader);
    }
}
于 2010-04-19T19:25:40.937 回答
3

一个简单的通用包装器：

public class GenericSerializer<T> : XmlSerializer
{
    public GenericSerializer(): base(typeof(T)) { }
}

这会将您的对象序列化到 bin/debug 文件夹：

static void Main(string[] args)
{
   Person p = new Person { Name = "HelloWorld" };
   GenericSerializer<Person> ser = new GenericSerializer<Person>();
   ser.Serialize(new StreamWriter("person.xml"), p);
}
于 2014-03-17T20:12:01.610 回答
1

尝试这个。

public class SerializeConfig<T> where T : class
{
    public static void Serialize(string path, T type)
    {
        var serializer = new XmlSerializer(type.GetType());
        using (var writer = new FileStream(path, FileMode.Create))
        {
            serializer.Serialize(writer, type);
        }
    }

    public static T DeSerialize(string path)
    {
        T type;
        var serializer = new XmlSerializer(typeof(T));
        using (var reader = XmlReader.Create(path))
        {
            type = serializer.Deserialize(reader) as T;
        }
        return type;
    }
}
于 2016-05-12T06:21:47.763 回答
1

总是为我工作 

  public static string ObjectToXmlSerialize<T>(T dataToSerialize)
    {
        try
        {
            var stringwriter = new System.IO.StringWriter();
            var serializer = new XmlSerializer(typeof(T));
            serializer.Serialize(stringwriter, dataToSerialize);
            return stringwriter.ToString();
        }
        catch (Exception ex)
        {
        }
        return null;
    }

这是用于反序列化：

  public static T XmlDeserializeToObject<T>(string xmlText)
    {
        try
        {
            var stringReader = new System.IO.StringReader(xmlText);
            var serializer = new XmlSerializer(typeof(T));
            return (T)serializer.Deserialize(stringReader);
        }
        catch (Exception ex)
        {
        }
        return default(T);
    }
于 2018-01-15T14:26:14.280 回答