问题:有多个线程访问一个资源。我需要将它们的数量限制为一个常数MaxThreads
。无法进入线程池的线程应该会收到错误消息。
解决方案:我开始BlockingCollection<string> pool
在下面的算法中使用 a ,但我看到这BlockingCollection
需要调用CompleteAdding
,我不能这样做,因为我总是得到传入线程(为了调试目的,我在下面的示例中硬编码为 10 ),想想网络请求.
public class MyTest {
private const int MaxThreads = 3;
private BlockingCollection<string> pool;
public MyTest() {
pool = new BlockingCollection<string>(MaxThreads);
}
public void Go() {
var addSuccess = this.pool.TryAdd(string.Format("thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
if (!addSuccess) Console.WriteLine(string.Format("thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
Console.WriteLine(string.Format("Adding thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
Console.WriteLine(string.Format("Pool size: {0}", pool.Count));
// simulate work
Thread.Sleep(1000);
Console.WriteLine("Thread ID#{0} " + Thread.CurrentThread.ManagedThreadId + " is done doing work.");
string val;
var takeSuccess = this.pool.TryTake(out val);
if (!takeSuccess) Console.WriteLine(string.Format("Failed to take out thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
Console.WriteLine("Taking out " + val);
Console.WriteLine(string.Format("Pool size: {0}", pool.Count));
Console.WriteLine(Environment.NewLine);
}
}
static void Main()
{
var t = new MyTest();
Parallel.For(0, 10, x => t.Go());
}
关于如何更好地实现这一目标的任何想法?
谢谢!
PS这里是多线程新手,如果您对阅读材料有任何建议,我将不胜感激。
LE:根据我得到的答案,我能够使用以下算法实现所需的行为:
public class MyTest {
private const int MaxThreads = 3;
private SemaphoreSlim semaphore;
public MyTest() {
semaphore = new SemaphoreSlim(MaxThreads, MaxThreads);
}
public void Go() {
Console.WriteLine(string.Format("In comes thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
semaphore.Wait();
try {
Console.WriteLine(string.Format("Serving thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
// simulate work
Thread.Sleep(1000);
Console.WriteLine(string.Format("Out goes thread ID#{0}", Thread.CurrentThread.ManagedThreadId));
}
finally {
semaphore.Release();
}
}
}
static void Main()
{
var t = new MyTest();
Parallel.For(0, 10, x=> t.Go());
}