值得考虑您想要的 JSON。
假设你有这门课
class Person
{
public string Name { get; set; }
public PhoneNumber HomePhone { get; set; }
}
您希望将其序列化为 JSON,如下所示
{ "Name":"Joe", "HomePhone": "555-555-555" }
但是你得到的是 JSON,像这样
{ "Name":"Joe","HomePhone": {"Number": "555-555-555"} }
--
要了解为什么会这样,请考虑属性Number of Person是一个object。JSON 至少需要一个{}来包装对象,或者更确切地说,是 {} 中的一组名称/值。
如果您真的非常想要以前的 JSON 语法,您需要为Person对象注册一个自定义转换器,以便您可以说服它将序列化和反序列化为字符串。(见下面的代码示例)。
但是,我建议您接受这一点,因为 PhoneNumber 是一个对象,它在序列化为 JSON 时对应于名称/值字典,并接受 JSON 看起来比您理想中的“干净”少一点。
FWIW 这是一个实现您最初目标的代码示例(不是推荐的方法)..
class Person
{
public string Name { get; set; }
public PhoneNumber HomeNumber { get; set; }
}
struct PhoneNumber
{
private string _number;
public PhoneNumber(string number)
{
_number = number;
}
public override string ToString()
{
return _number;
}
}
class PersonConverter : JavaScriptConverter
{
public override IEnumerable<Type> SupportedTypes
{
get { yield return typeof(Person); }
}
public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{
Person person = obj as Person;
if (person != null)
{
Dictionary<string, object> dict = new Dictionary<string, object>();
dict["Name"] = person.Name;
dict["HomeNumber"] = person.HomeNumber.ToString();
return dict;
}
return new Dictionary<string, object>();
}
public override object Deserialize(IDictionary<string, object> dict, Type type, JavaScriptSerializer serializer)
{
if (dict == null)
throw new ArgumentNullException("dict");
if (type == typeof(Person))
{
// Deserialize the Person's single property.
string name = (string)dict["Name"];
string homeNumber = (string)dict["HomeNumber"];
// Create the instance to deserialize into.
Person person = new Person()
{
Name = name,
HomeNumber = new PhoneNumber(homeNumber)
};
return person;
}
return null;
}
}
class Program
{
static void Main(string[] args)
{
PhoneNumber number = new PhoneNumber("555 555");
Person joe = new Person() { Name = "Joe", HomeNumber = number };
JavaScriptSerializer serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new JavaScriptConverter[] { new PersonConverter() });
Console.Out.WriteLine(serializer.Serialize(joe));
}
}