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我是 WinRT c++ 的新手。我正在尝试从 C# 传递 StorageFile 图像并打开文件并将其设置为 WinRT 中 BitmapImage 中的源以提取图像的高度和宽度。我正在使用以下代码。

auto openOperation = StorageImageFile->OpenAsync(FileAccessMode::Read); // from http://msdn.microsoft.com/en-us/library/windows/desktop/hh780393%28v=vs.85%29.aspx
openOperation->Completed = ref new
    AsyncOperationCompletedHandler<IRandomAccessStream^>(
    [=](IAsyncOperation<IRandomAccessStream^> ^operation, AsyncStatus status)
{
    auto Imagestream = operation->GetResults(); 
    BitmapImage^ bmp = ref new BitmapImage();
    auto bmpOp = bmp->SetSourceAsync(Imagestream);
    bmpOp->Completed = ref new 
        AsyncActionCompletedHandler (
        [=](IAsyncAction^ action, AsyncStatus status)
    {
        action->GetResults();
        UINT32 imageWidth = (UINT32)bmp->PixelWidth;
        UINT32 imageHeight = (UINT32)bmp->PixelHeight;
    });
});

此代码似乎不起作用。在 BitmapImage^ bmp = ref new BitmapImage(); 之后 调试器停止说没有找到源代码。你能帮我写出正确的代码吗？

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1 回答 1

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我想你的意思是写和。我不是 C++ 专家，但据我所知 - 异步操作通常包含在调用中。不太清楚为什么 - 也许是为了避免在不取消订阅的情况下订阅事件？openOperation->Completed += ref new...bmpOp->Completed += ref new...create_task

我认为它应该大致是这样的：

auto bmp = ref new BitmapImage();

create_task(storageImageFile->OpenAsync(FileAccessMode::Read)) // get the stream
    .then([bmp](IRandomAccessStream^ ^stream) // continuation lambda
{
    return create_task(bmp->SetSourceAsync(stream)); // needs to run on ASTA/Dispatcher thread
}, task_continuation_context::use_current()) // run on ASTA/Dispatcher thread
    .then([bmp]() // continuation lambda
{
        UINT32 imageWidth = (UINT32)bmp->PixelWidth; // needs to run on ASTA/Dispatcher thread
        UINT32 imageHeight = (UINT32)bmp->PixelHeight; // needs to run on ASTA/Dispatcher thread

        // TODO: use imageWidth and imageHeight
}, task_continuation_context::use_current()); // run on ASTA/Dispatcher thread
于 2014-09-19T15:39:17.393 回答