我已经购买了 LinkSprite JPEG 彩色相机和一个 LPC1768 mbed 微控制器。通过“LinkSprite”相机,我可以拍摄 jpeg 格式的图像,根据他们提供的教程,我可以传输并在桌面上查看这些图像。但我想在“LPC1768 mbed”微控制器中处理这些图像。例如,我想循环通过该图像的每一行和每一列来匹配一种颜色。谁能告诉我如何将整个图像接收到二维数组中,然后循环遍历数组以匹配红色等颜色。当我传输图像时,数据看起来像另一个问题。ff d8 ff e0 00 10 .........40 c6 81 90 b9 aa ee 68 19 ff d9。我知道 jpeg 图像以 ff d9 开头并以 ff d9 结尾。但是我如何在这些值中识别一个像素,我如何比较颜色是否与红色匹配???
摄像头拍照并逐字节传输图像的代码
int main() {
JPEGCamera camera(p9, p10); // TX, RX
LocalFileSystem local("local"); //save images on mbed
Timer timer;
timer.start();
if(camera.setPictureSize(JPEGCamera::SIZE160x120))
{
myled1 = 1;
wait(2.0);
myled1 = 0;
wait(2.0);
}
for (int i = 1; i < 3; i++) {
if (camera.isReady()) {
char filename[32];
sprintf(filename, "/local/pict%03d.jpg", i);
printf("Picture: %s \n", filename);
if (camera.takePicture(filename)) {
while (camera.isProcessing()) {
camera.processPicture();
}
myled1 = 1; //show successful picture was taken
wait(2.0);
myled1 = 0;
} else {
printf("take picture failed\n");
myled3 = 1; //show picture take failed
wait(2.0);
myled3 = 0;
}
} else {
printf("camera is not ready\n");
myled4 = 1; //show camera is not ready
wait(2.0);
myled4 = 0;
}
}
在 JPEGCamera.cpp
bool JPEGCamera::processPicture() {
if (state == PROCESSING) {
bt.printf("\n\nNew Image \n\n");
if (address < imageSize) {
char data[2048];
int size = readData(data, min(sizeof(data), imageSize - address), address);
int ret = fwrite(data, size, 1, fp);
for (int i=0; i<size; i++) bt.printf("%x ",data[i]);
if (ret > 0)
address += size;
if (ret == 0 || address >= imageSize) {
stopPictures();
fclose(fp);
wait(0.1); // ????
state = ret > 0 ? READY : ERROR;
}
}
}
return state == PROCESSING || state == READY;
}
有什么方法可以将图像字节存储在“processPicture”函数的数组中?有什么方法可以让我简单地读取存储的图像???