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我在文件中将“19851003”作为出生日期传递，但在日志文件中出现以下错误。

ORA-01841: (full) year must be between -4713 and +9999, and not be 0

知道为什么会出现错误，因为我只将它作为字符串传递

日志文件中的错误：

error processing column DATE_OF_BIRTH in row 2 for datafile /xfer/x/directory/filename.csv
ORA-01841: (full) year must be between -4713 and +9999, and not be 0

我的表代码：

CREATE TABLE table_name
(
  ID                  VARCHAR2(10 BYTE),      
  FIRST_NAME          VARCHAR2(150 BYTE),
  LAST_NAME           VARCHAR2(150 BYTE),
  MIDDLE_NAME         VARCHAR2(150 BYTE),
  DATE_OF_BIRTH       DATE
)

ORGANIZATION EXTERNAL
( TYPE ORACLE_LOADER
  DEFAULT DIRECTORY DIRECTORY_TABLES
  ACCESS PARAMETERS 
  (RECORDS  DELIMITED BY '\n'
   SKIP 1
   BADFILE  DIRECTORY_TABLES:'filelist.bad'
   LOGFILE  DIRECTORY_TABLES:'filelist.log'
   DISCARDFILE   DIRECTORY_TABLES:'filelist.dsc'
   FIELDS TERMINATED BY ','
   OPTIONALLY ENCLOSED BY '"'
   MISSING FIELD VALUES ARE NULL
   REJECT ROWS WITH ALL NULL FIELDS
   (ID                  ,
    FIRST_NAME          ,
    LAST_NAME           ,
    MIDDLE_NAME         ,
    DATE_OF_BIRTH       DATE "YYYYMMDD" 
   )
)
LOCATION (DIRECTORY_TABLES:'filename.csv')
)
REJECT LIMIT 0
NOPARALLEL
NOMONITORING;

我的 CSV 文件：

"id","First Name","Last Name","MI","DOB"
"2","Felicia","Brown","M","19810209"
"3","Jose","Romero","M","19890706"
"4","Valerie","Moore","","19621112"
4

2 回答 2

2

在 DATE_OF_BIRTH 的规范中，需要一个日期格式规范。尝试：

DATE_OF_BIRTH  CHAR DATE_FORMAT DATE MASK "YYYYMMDD"

参考这里然后搜索“date_format_spec”

分享和享受。

于 2014-08-23T16:05:13.733 回答
0

正如错误所说，19851003 不在 -4713 和 9999 之间。

我怀疑你想通过 1985 作为年份并且你不小心通过了一个完整的日期 (yyyyMmdd)

于 2014-08-23T06:57:06.840 回答