我正在寻找 Java 中的 KDTree 实现。
我做了一个谷歌搜索，结果似乎很随意。实际上有很多结果，但它们大多只是一次性的实现，我宁愿找到更多“生产价值”的东西。诸如 apache 集合或 .NET 的优秀 C5 集合库之类的东西。我可以看到公共错误跟踪器并检查最后一次 SVN 提交发生的时间。此外，在理想情况下，我会为空间数据结构找到一个精心设计的 API，而 KDTree 只是该库中的一个类。
对于这个项目，我只会在 2 维或 3 维中工作，而且我主要只是对一个好的最近邻实现感兴趣。
benjismith
问问题
48749 次
10 回答
25
在Algorithms in a Nutshell一书中，Java 中有一个 kd 树实现以及一些变体。所有代码都在oreilly.com上，这本书本身也将引导您完成算法，以便您自己构建一个。
于 2008-11-06T15:26:21.647 回答
17
对于未来的寻求者。Java-ml 库有一个运行良好的 kd-tree 实现。 http://java-ml.sourceforge.net/
于 2011-11-14T11:15:58.740 回答
11
我在此处找到的 Levy 教授的实施取得了成功。我意识到您正在寻找更多经过生产认证的实施，因此这可能不太合适。
但是请注意任何路人，我已经在我的照片马赛克项目中使用它一段时间了，没有任何问题。没有保证，但总比没有好:)
于 2010-05-06T20:12:44.960 回答
4
我创建了一个 KD-Tree 实现作为离线反向地理编码库的一部分
于 2014-06-13T12:45:29.000 回答
3
也许来自 Stony-Brook 算法存储库的最近邻搜索和KD-trees可以提供帮助。
于 2008-11-03T21:39:33.673 回答
2
这是 KD-Tree 的完整实现，我使用了一些库来存储点和矩形。这些库是免费提供的。可以使用这些类创建自己的类来存储点和矩形。请分享您的反馈。
import java.util.ArrayList;
import java.util.List;
import edu.princeton.cs.algs4.In;
import edu.princeton.cs.algs4.Point2D;
import edu.princeton.cs.algs4.RectHV;
import edu.princeton.cs.algs4.StdDraw;
public class KdTree {
private static class Node {
public Point2D point; // the point
public RectHV rect; // the axis-aligned rectangle corresponding to this
public Node lb; // the left/bottom subtree
public Node rt; // the right/top subtree
public int size;
public double x = 0;
public double y = 0;
public Node(Point2D p, RectHV rect, Node lb, Node rt) {
super();
this.point = p;
this.rect = rect;
this.lb = lb;
this.rt = rt;
x = p.x();
y = p.y();
}
}
private Node root = null;;
public KdTree() {
}
public boolean isEmpty() {
return root == null;
}
public int size() {
return rechnenSize(root);
}
private int rechnenSize(Node node) {
if (node == null) {
return 0;
} else {
return node.size;
}
}
public void insert(Point2D p) {
if (p == null) {
throw new NullPointerException();
}
if (isEmpty()) {
root = insertInternal(p, root, 0);
root.rect = new RectHV(0, 0, 1, 1);
} else {
root = insertInternal(p, root, 1);
}
}
// at odd level we will compare x coordinate, and at even level we will
// compare y coordinate
private Node insertInternal(Point2D pointToInsert, Node node, int level) {
if (node == null) {
Node newNode = new Node(pointToInsert, null, null, null);
newNode.size = 1;
return newNode;
}
if (level % 2 == 0) {//Horizontal partition line
if (pointToInsert.y() < node.y) {//Traverse in bottom area of partition
node.lb = insertInternal(pointToInsert, node.lb, level + 1);
if(node.lb.rect == null){
node.lb.rect = new RectHV(node.rect.xmin(), node.rect.ymin(),
node.rect.xmax(), node.y);
}
} else {//Traverse in top area of partition
if (!node.point.equals(pointToInsert)) {
node.rt = insertInternal(pointToInsert, node.rt, level + 1);
if(node.rt.rect == null){
node.rt.rect = new RectHV(node.rect.xmin(), node.y,
node.rect.xmax(), node.rect.ymax());
}
}
}
} else if (level % 2 != 0) {//Vertical partition line
if (pointToInsert.x() < node.x) {//Traverse in left area of partition
node.lb = insertInternal(pointToInsert, node.lb, level + 1);
if(node.lb.rect == null){
node.lb.rect = new RectHV(node.rect.xmin(), node.rect.ymin(),
node.x, node.rect.ymax());
}
} else {//Traverse in right area of partition
if (!node.point.equals(pointToInsert)) {
node.rt = insertInternal(pointToInsert, node.rt, level + 1);
if(node.rt.rect == null){
node.rt.rect = new RectHV(node.x, node.rect.ymin(),
node.rect.xmax(), node.rect.ymax());
}
}
}
}
node.size = 1 + rechnenSize(node.lb) + rechnenSize(node.rt);
return node;
}
public boolean contains(Point2D p) {
return containsInternal(p, root, 1);
}
private boolean containsInternal(Point2D pointToSearch, Node node, int level) {
if (node == null) {
return false;
}
if (level % 2 == 0) {//Horizontal partition line
if (pointToSearch.y() < node.y) {
return containsInternal(pointToSearch, node.lb, level + 1);
} else {
if (node.point.equals(pointToSearch)) {
return true;
}
return containsInternal(pointToSearch, node.rt, level + 1);
}
} else {//Vertical partition line
if (pointToSearch.x() < node.x) {
return containsInternal(pointToSearch, node.lb, level + 1);
} else {
if (node.point.equals(pointToSearch)) {
return true;
}
return containsInternal(pointToSearch, node.rt, level + 1);
}
}
}
public void draw() {
StdDraw.clear();
drawInternal(root, 1);
}
private void drawInternal(Node node, int level) {
if (node == null) {
return;
}
StdDraw.setPenColor(StdDraw.BLACK);
StdDraw.setPenRadius(0.02);
node.point.draw();
double sx = node.rect.xmin();
double ex = node.rect.xmax();
double sy = node.rect.ymin();
double ey = node.rect.ymax();
StdDraw.setPenRadius(0.01);
if (level % 2 == 0) {
StdDraw.setPenColor(StdDraw.BLUE);
sy = ey = node.y;
} else {
StdDraw.setPenColor(StdDraw.RED);
sx = ex = node.x;
}
StdDraw.line(sx, sy, ex, ey);
drawInternal(node.lb, level + 1);
drawInternal(node.rt, level + 1);
}
/**
* Find the points which lies in the rectangle as parameter
* @param rect
* @return
*/
public Iterable<Point2D> range(RectHV rect) {
List<Point2D> resultList = new ArrayList<Point2D>();
rangeInternal(root, rect, resultList);
return resultList;
}
private void rangeInternal(Node node, RectHV rect, List<Point2D> resultList) {
if (node == null) {
return;
}
if (node.rect.intersects(rect)) {
if (rect.contains(node.point)) {
resultList.add(node.point);
}
rangeInternal(node.lb, rect, resultList);
rangeInternal(node.rt, rect, resultList);
}
}
public Point2D nearest(Point2D p) {
if(root == null){
return null;
}
Champion champion = new Champion(root.point,Double.MAX_VALUE);
return nearestInternal(p, root, champion, 1).champion;
}
private Champion nearestInternal(Point2D targetPoint, Node node,
Champion champion, int level) {
if (node == null) {
return champion;
}
double dist = targetPoint.distanceSquaredTo(node.point);
int newLevel = level + 1;
if (dist < champion.championDist) {
champion.champion = node.point;
champion.championDist = dist;
}
boolean goLeftOrBottom = false;
//We will decide which part to be visited first, based upon in which part point lies.
//If point is towards left or bottom part, we traverse in that area first, and later on decide
//if we need to search in other part too.
if(level % 2 == 0){
if(targetPoint.y() < node.y){
goLeftOrBottom = true;
}
} else {
if(targetPoint.x() < node.x){
goLeftOrBottom = true;
}
}
if(goLeftOrBottom){
nearestInternal(targetPoint, node.lb, champion, newLevel);
Point2D orientationPoint = createOrientationPoint(node.x,node.y,targetPoint,level);
double orientationDist = orientationPoint.distanceSquaredTo(targetPoint);
//We will search on the other part only, if the point is very near to partitioned line
//and champion point found so far is far away from the partitioned line.
if(orientationDist < champion.championDist){
nearestInternal(targetPoint, node.rt, champion, newLevel);
}
} else {
nearestInternal(targetPoint, node.rt, champion, newLevel);
Point2D orientationPoint = createOrientationPoint(node.x,node.y,targetPoint,level);
//We will search on the other part only, if the point is very near to partitioned line
//and champion point found so far is far away from the partitioned line.
double orientationDist = orientationPoint.distanceSquaredTo(targetPoint);
if(orientationDist < champion.championDist){
nearestInternal(targetPoint, node.lb, champion, newLevel);
}
}
return champion;
}
/**
* Returns the point from a partitioned line, which can be directly used to calculate
* distance between partitioned line and the target point for which neighbours are to be searched.
* @param linePointX
* @param linePointY
* @param targetPoint
* @param level
* @return
*/
private Point2D createOrientationPoint(double linePointX, double linePointY, Point2D targetPoint, int level){
if(level % 2 == 0){
return new Point2D(targetPoint.x(),linePointY);
} else {
return new Point2D(linePointX,targetPoint.y());
}
}
private static class Champion{
public Point2D champion;
public double championDist;
public Champion(Point2D c, double d){
champion = c;
championDist = d;
}
}
public static void main(String[] args) {
String filename = "/home/raman/Downloads/kdtree/circle100.txt";
In in = new In(filename);
KdTree kdTree = new KdTree();
while (!in.isEmpty()) {
double x = in.readDouble();
double y = in.readDouble();
Point2D p = new Point2D(x, y);
kdTree.insert(p);
}
// kdTree.print();
System.out.println(kdTree.size());
kdTree.draw();
System.out.println(kdTree.nearest(new Point2D(0.4, 0.5)));
System.out.println(new Point2D(0.7, 0.4).distanceSquaredTo(new Point2D(0.9,0.5)));
System.out.println(new Point2D(0.7, 0.4).distanceSquaredTo(new Point2D(0.9,0.4)));
}
}
于 2017-03-09T21:40:53.453 回答
1
你是对的，没有多少网站有 Java 的 kd 实现！无论如何，kd 树基本上是一个二叉搜索树，通常每次都会为该维度计算中值。这是简单的 KDNode，就最近邻方法或完整实现而言，请查看此github项目。这是我能为你找到的最好的一个。希望这对您有所帮助。
private class KDNode {
KDNode left;
KDNode right;
E val;
int depth;
private KDNode(E e, int depth){
this.left = null;
this.right = null;
this.val = e;
this.depth = depth;
}
于 2014-12-14T07:40:40.083 回答
0
可能会引起某人的兴趣。请参阅我最近的（）（和 KD Tree 类）在 java 中的 2D 树实现：
import edu.princeton.cs.algs4.Point2D;
import edu.princeton.cs.algs4.RectHV;
import edu.princeton.cs.algs4.StdDraw;
import java.util.ArrayList;
import java.util.List;
public class KdTree {
private Node root;
private int size;
private static class Node {
private Point2D p; // the point
private RectHV rect; // the axis-aligned rectangle corresponding to this node
private Node lb; // the left/bottom subtree
private Node rt; // the right/top subtree
public Node(Point2D p, RectHV rect) {
this.p = p;
this.rect = rect;
}
}
public KdTree() {
}
public boolean isEmpty() {
return size == 0;
}
public int size() {
return size;
}
public boolean contains(Point2D p) {
if (p == null) throw new IllegalArgumentException("argument to contains() is null");
return contains(root, p, 1);
}
private boolean contains(Node node, Point2D p, int level) {
if (node == null) return false; // a base case for recursive call
if (node.p.equals(p)) return true;
if (level % 2 == 0) { // search by y coordinate (node with horizontal partition line)
if (p.y() < node.p.y())
return contains(node.lb, p, level + 1);
else
return contains(node.rt, p, level + 1);
}
else { // search by x coordinate (node with vertical partition line)
if (p.x() < node.p.x())
return contains(node.lb, p, level + 1);
else
return contains(node.rt, p, level + 1);
}
}
public void insert(Point2D p) {
if (p == null) throw new IllegalArgumentException("calls insert() with a null point");
root = insert(root, p, 1);
}
private Node insert(Node x, Point2D p, int level) {
if (x == null) {
size++;
return new Node(p, new RectHV(0, 0, 1, 1));
}
if (x.p.equals(p)) return x; // if we try to insert existed point just return its node
if (level % 2 == 0) { // search by y coordinate (node with horizontal partition line)
if (p.y() < x.p.y()) {
x.lb = insert(x.lb, p, level + 1);
if (x.lb.rect.equals(root.rect))
x.lb.rect = new RectHV(x.rect.xmin(), x.rect.ymin(), x.rect.xmax(), x.p.y());
}
else {
x.rt = insert(x.rt, p, level + 1);
if (x.rt.rect.equals(root.rect))
x.rt.rect = new RectHV(x.rect.xmin(), x.p.y(), x.rect.xmax(), x.rect.ymax());
}
}
else { // search by x coordinate (node with vertical partition line)
if (p.x() < x.p.x()) {
x.lb = insert(x.lb, p, level + 1);
if (x.lb.rect.equals(root.rect))
x.lb.rect = new RectHV(x.rect.xmin(), x.rect.ymin(), x.p.x(), x.rect.ymax());
}
else {
x.rt = insert(x.rt, p, level + 1);
if (x.rt.rect.equals(root.rect))
x.rt.rect = new RectHV(x.p.x(), x.rect.ymin(), x.rect.xmax(), x.rect.ymax());
}
}
return x;
}
public void draw() {
draw(root, 1);
}
private void draw(Node node, int level) {
if (node == null) return;
StdDraw.setPenColor(StdDraw.BLACK);
StdDraw.setPenRadius(0.01);
node.p.draw();
StdDraw.setPenRadius();
if (level % 2 == 0) {
StdDraw.setPenColor(StdDraw.BLUE);
StdDraw.line(node.rect.xmin(), node.p.y(), node.rect.xmax(), node.p.y());
}
else {
StdDraw.setPenColor(StdDraw.RED);
StdDraw.line(node.p.x(), node.rect.ymin(), node.p.x(), node.rect.ymax());
}
draw(node.lb, level + 1);
draw(node.rt, level + 1);
}
public Iterable<Point2D> range(RectHV rect) {
if (rect == null) throw new IllegalArgumentException("calls range() with a null rect");
List<Point2D> points = new ArrayList<>(); // create an Iterable object with all points we found
range(root, rect, points); // call helper method with rects intersects comparing
return points; // return an Iterable object (It could be any type - Queue, LinkedList etc)
}
private void range(Node node, RectHV rect, List<Point2D> points) {
if (node == null || !node.rect.intersects(rect)) return; // a base case for recursive call
if (rect.contains(node.p))
points.add(node.p);
range(node.lb, rect, points);
range(node.rt, rect, points);
}
public Point2D nearest(Point2D query) {
if (isEmpty()) return null;
if (query == null) throw new IllegalArgumentException("calls nearest() with a null point");
// set the start distance from root to query point
double best = root.p.distanceSquaredTo(query);
// StdDraw.setPenColor(StdDraw.BLACK); // just for debugging
// StdDraw.setPenRadius(0.01);
// query.draw();
return nearest(root, query, root.p, best, 1); // call a helper method
}
private Point2D nearest(Node node, Point2D query, Point2D champ, double best, int level) {
// a base case for the recursive call
if (node == null || best < node.rect.distanceSquaredTo(query)) return champ;
// we'll need to set an actual best distance when we recur
best = champ.distanceSquaredTo(query);
// check whether a distance from query point to the traversed node less than
// distance from current champion to query point
double temp = node.p.distanceSquaredTo(query);
if (temp < best) {
best = temp;
champ = node.p;
}
if (level % 2 == 0) { // search by y coordinate (node with horizontal partition line)
// we compare y coordinate and decide go up or down
if (node.p.y() < query.y()) { // if true go up
champ = nearest(node.rt, query, champ, best, level + 1);
// important case - when we traverse node and go back up through the tree
// we need to decide whether we need to go down(left) in this node or not
// we just check our bottom (left) node on null && compare distance
// from query point to the nearest point of the node's rectangle and
// the distance from current champ point to thr query point
if (node.lb != null && node.lb.rect.distanceSquaredTo(query) < champ.distanceSquaredTo(query)) {
champ = nearest(node.lb, query, champ, best, level + 1);
}
}
else { // if false go down
champ = nearest(node.lb, query, champ, best, level + 1);
if (node.rt != null && node.rt.rect.distanceSquaredTo(query) < champ.distanceSquaredTo(query))
// when we traverse node and go back up through the tree
// we need to decide whether we need to go up(right) in this node or not
// we just check our top (right) node on null && compare distance
// from query point to the nearest point of the node's rectangle and
// the distance from current champ point to thr query point
champ = nearest(node.rt, query, champ, best, level + 1);
}
}
else {
// search by x coordinate (node with vertical partition line)
if (node.p.x() < query.x()) { // if true go right
champ = nearest(node.rt, query, champ, best, level + 1);
// the same check as mentioned above when we search by y coordinate
if (node.lb != null && node.lb.rect.distanceSquaredTo(query) < champ.distanceSquaredTo(query))
champ = nearest(node.lb, query, champ, best, level + 1);
}
else { // if false go left
champ = nearest(node.lb, query, champ, best, level + 1);
if (node.rt != null && node.rt.rect.distanceSquaredTo(query) < champ.distanceSquaredTo(query))
champ = nearest(node.rt, query, champ, best, level + 1);
}
}
return champ;
}
public static void main(String[] args) {
// unit tests
KdTree kd = new KdTree();
Point2D p1 = new Point2D(0.7, 0.2);
Point2D p2 = new Point2D(0.5, 0.4);
Point2D p3 = new Point2D(0.2, 0.3);
Point2D p4 = new Point2D(0.4, 0.7);
Point2D p5 = new Point2D(0.9, 0.6);
// Point2D query = new Point2D(0.676, 0.736);
Point2D query1 = new Point2D(0.972, 0.887);
// RectHV test = new RectHV(0, 0, 0.7, 0.4);
// Point2D query = new Point2D(0.331, 0.762);
// Point2D p6 = new Point2D(0.4, 0.4);
// Point2D p7 = new Point2D(0.1, 0.6);
// RectHV rect = new RectHV(0.05, 0.1, 0.15, 0.6);
kd.insert(p1);
kd.insert(p2);
kd.insert(p3);
kd.insert(p4);
kd.insert(p5);
System.out.println(kd.nearest(query1));
// System.out.println("Dist query to 0.4,0.7= " + query.distanceSquaredTo(p4));
// System.out.println("Dist query to RectHV 0.2,0,3= " + test.distanceSquaredTo(p4));
// kd.insert(p6);
// kd.insert(p7);
// System.out.println(kd.size);
// System.out.println(kd.contains(p3));
// // System.out.println(kd.range(rect));
kd.draw();
}
}
于 2022-02-28T16:36:04.663 回答
-1
package kdtree;
class KDNode{
KDNode left;
KDNode right;
int []data;
public KDNode(){
left=null;
right=null;
}
public KDNode(int []x){
left=null;
right=null;
data = new int[2];
for (int k = 0; k < 2; k++)
data[k]=x[k];
}
}
class KDTreeImpl{
KDNode root;
int cd=0;
int DIM=2;
public KDTreeImpl() {
root=null;
}
public boolean isEmpty(){
return root == null;
}
public void insert(int []x){
root = insert(x,root,cd);
}
private KDNode insert(int []x,KDNode t,int cd){
if (t == null)
t = new KDNode(x);
else if (x[cd] < t.data[cd])
t.left = insert(x, t.left, (cd+1)%DIM);
else
t.right = insert(x, t.right, (cd+1)%DIM);
return t;
}
public boolean search(int []data){
return search(data,root,0);
}
private boolean search(int []x,KDNode t,int cd){
boolean found=false;
if(t==null){
return false;
}
else {
if(x[cd]==t.data[cd]){
if(x[0]==t.data[0] && x[1]==t.data[1])
return true;
}else if(x[cd]<t.data[cd]){
found = search(x,t.left,(cd+1)%DIM);
}else if(x[cd]>t.data[cd]){
found = search(x,t.right,(cd+1)%DIM);
}
return found;
}
}
public void inorder(){
inorder(root);
}
private void inorder(KDNode r){
if (r != null){
inorder(r.left);
System.out.print("("+r.data[0]+","+r.data[1] +") ");
inorder(r.right);
}
}
public void preorder() {
preorder(root);
}
private void preorder(KDNode r){
if (r != null){
System.out.print("("+r.data[0]+","+r.data[1] +") ");
preorder(r.left);
preorder(r.right);
}
}
/* Function for postorder traversal */
public void postorder() {
postorder(root);
}
private void postorder(KDNode r) {
if (r != null){
postorder(r.left);
postorder(r.right);
System.out.print("("+r.data[0]+","+r.data[1] +") ");
}
}
}
public class KDTree {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
KDTreeImpl kdt = new KDTreeImpl();
int x[] = new int[2];
x[0] = 30;
x[1] = 40;
kdt.insert(x);
x[0] = 5;
x[1] = 25;
kdt.insert(x);
x[0] = 10;
x[1] = 12;
kdt.insert(x);
x[0] = 70;
x[1] = 70;
kdt.insert(x);
x[0] = 50;
x[1] = 30;
kdt.insert(x);
System.out.println("Input Elements");
System.out.println("(30,40) (5,25) (10,12) (70,70) (50,30)\n\n");
System.out.println("Printing KD Tree in Inorder");
kdt.inorder();
System.out.println("\nPrinting KD Tree in PreOder");
kdt.preorder();
System.out.println("\nPrinting KD Tree in PostOrder");
kdt.postorder();
System.out.println("\nsearching...............");
x[0]=40;x[1]=40;
System.out.println(kdt.search(x));
}
}
于 2016-12-31T17:25:09.840 回答