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我使用 FNV 在我的 32 位操作系统中散列文件。如果我在 64 位操作系统中使用代码，为什么相同代码的哈希结果会不同？

这是我的代码：

function gethash(const dwOffset: PByteArray; const dwLen: DWORD;
  const offset_basis: DWORD): DWORD;
var
  i: integer;
begin
  Result := offset_basis;
  try
    {$R-}{$I-}
    for i := 0 to dwLen - 1 do
      Result := (Result * 16777619) xor DWORD(dwOffset^[i]);
    {$R+}{$I+}
  except
    ;
  end;
end;
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1 回答 1

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This code will produce the same output irrespective of the bitness of the operating system. Furthermore the output is independent of the bitness of the process. That is, if you compile for 32 bit and 64 bit, the output will be the same.

The logical conclusion therefore, is that the different output is caused by supplying different input.

One might ask why you have a swallow all exception handler in your code. That must be a really bad idea. If you supply incorrect parameters which lead to an access violation, you'll never find out. I urge you to remove that exception handler.

To demonstrate my point, I offer the following simple test program:

{$APPTYPE CONSOLE}

uses
  Winapi.Windows,
  System.SysUtils;

{$R-}{$I-}
function gethash(const dwOffset: PByteArray; const dwLen: DWORD;
  const offset_basis: DWORD): DWORD;
var
  i: integer;
begin
  Result := offset_basis;
  for i := 0 to dwLen - 1 do
    Result := (Result * 16777619) xor DWORD(dwOffset^[i]);
end;

procedure Main;
var
  i: Integer;
  buf: TBytes;
begin
  SetLength(buf, 666);
  for i := 0 to high(buf) do
    buf[i] := (i+13)*7 mod 256;
  Writeln(gethash(PByteArray(buf), Length(buf), 17));
end;

begin
  Main;
  Readln;
end.

This produces the same output on every operating system, and the same output when compiled by either the 32 bit or 64 bit compiler. Whilst this does not prove that will be the case for every possible input, it gives you a test bed. You can replace my input with your own and you will discover, if I am right, that the output will always be the same, for fixed input.

One plausible explanation for your problem is that you are reading beyond the end of the buffer and so hashing ill-defined input data. And perhaps with a different OS or compiler, that ill-defined input data differs.

于 2014-08-14T09:18:03.013 回答