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我无法让我的脚本在不同的文件夹中工作。对 Google App Engine 来说非常新，对 YAML 来说是全新的。

文件夹结构为：

/login.php
/includes/mySQLConnection.php

应用程序.yaml

application: test
version: 1
runtime: php
api_version: 1

handlers:
- url: /includes
  static_dir: includes
  application_readable: true
- url: /login.php
  script: login.php

登录.php

<?php
    header('Content-type: application/json');

    if($_POST) {
    //Get Username and Password
    $user_email = strip_tags(trim(strtolower($_POST['username'])));
    $user_password = strip_tags(trim($_POST['password']));

    //Connect to mySQL Server
    include $_SERVER['DOCUMENT_ROOT']."includes/mySQL_connection.php";

    // //Select which database to work with
    $database = mysql_select_db("test",$mySQL_connection) or die("Cannot connect to user table");

            echo json_encode(array('success' => 1,'error_message' => "Success"));
    }
?>

/includes/mySQL_connection.php

<?php
    $hostname = '127.0.0.1:3306'; 
    $db_username = 'root';
    $db_password = '';

    //connection to the database
    $mySQL_connection = mysql_connect($hostname, $db_username, $db_password) or die("Unable to connect to MySQL");
?>

这行不通，但是如果我从 /includes/mySQL_connection.php 中取出所有代码并将其放入 /login.php 中，那么它可以完美运行。

谁能指出我正确的方向？

4

1 回答 1

1

DOCUMENT_ROOT 没有尾随的“/”，看起来您需要添加一个。

在http://php-minishell.appspot.com/我试过了

>>> echo $_SERVER['DOCUMENT_ROOT'];
/base/data/home/apps/s~php-minishell/20140319.374522287571266149

所以可能将您的代码更改为

   //Connect to mySQL Server
    include $_SERVER['DOCUMENT_ROOT']."/includes/mySQL_connection.php";
于 2014-06-19T15:09:13.267 回答