54

我正在尝试使用 Java 播放 *.wav 文件。我希望它执行以下操作：
按下按钮时，播放短促的哔声。

我用谷歌搜索了它，但大部分代码都不起作用。有人可以给我一个简单的代码片段来播放 .wav 文件吗？

4

9 回答 9

44

最后我设法做到了以下，它工作正常 

import java.io.File;
import java.io.IOException;

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;

public class MakeSound {

    private final int BUFFER_SIZE = 128000;
    private File soundFile;
    private AudioInputStream audioStream;
    private AudioFormat audioFormat;
    private SourceDataLine sourceLine;

    /**
     * @param filename the name of the file that is going to be played
     */
    public void playSound(String filename){

        String strFilename = filename;

        try {
            soundFile = new File(strFilename);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }

        try {
            audioStream = AudioSystem.getAudioInputStream(soundFile);
        } catch (Exception e){
            e.printStackTrace();
            System.exit(1);
        }

        audioFormat = audioStream.getFormat();

        DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
        try {
            sourceLine = (SourceDataLine) AudioSystem.getLine(info);
            sourceLine.open(audioFormat);
        } catch (LineUnavailableException e) {
            e.printStackTrace();
            System.exit(1);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }

        sourceLine.start();

        int nBytesRead = 0;
        byte[] abData = new byte[BUFFER_SIZE];
        while (nBytesRead != -1) {
            try {
                nBytesRead = audioStream.read(abData, 0, abData.length);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (nBytesRead >= 0) {
                @SuppressWarnings("unused")
                int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
            }
        }

        sourceLine.drain();
        sourceLine.close();
    }
}
于 2010-03-12T14:45:24.660 回答
40

这是我在不使用 sun 的情况下能想到的最优雅的形式。*：

import java.io.*;
import javax.sound.sampled.*;

try {
    File yourFile;
    AudioInputStream stream;
    AudioFormat format;
    DataLine.Info info;
    Clip clip;

    stream = AudioSystem.getAudioInputStream(yourFile);
    format = stream.getFormat();
    info = new DataLine.Info(Clip.class, format);
    clip = (Clip) AudioSystem.getLine(info);
    clip.open(stream);
    clip.start();
}
catch (Exception e) {
    //whatevers
}
于 2012-06-14T00:52:45.503 回答
17

最短形式（无需安装随机库）？

public static void play(String filename)
{
    try
    {
        Clip clip = AudioSystem.getClip();
        clip.open(AudioSystem.getAudioInputStream(new File(filename)));
        clip.start();
    }
    catch (Exception exc)
    {
        exc.printStackTrace(System.out);
    }
}

唯一的问题是没有好的方法可以使此方法阻塞以在 *.wav 完成后关闭和处理数据。 clip.drain()说它正在阻塞，但事实并非如此。剪辑没有运行RIGHT AFTER start()。我发现的唯一有效但丑陋的方法是：

// ...
clip.start();
while (!clip.isRunning())
    Thread.sleep(10);
while (clip.isRunning())
    Thread.sleep(10);
clip.close();
于 2012-07-17T01:20:03.480 回答
15

您可以使用事件侦听器在播放后关闭剪辑

import java.io.File;
import javax.sound.sampled.*;

public void play(File file) 
{
    try
    {
        final Clip clip = (Clip)AudioSystem.getLine(new Line.Info(Clip.class));

        clip.addLineListener(new LineListener()
        {
            @Override
            public void update(LineEvent event)
            {
                if (event.getType() == LineEvent.Type.STOP)
                    clip.close();
            }
        });

        clip.open(AudioSystem.getAudioInputStream(file));
        clip.start();
    }
    catch (Exception exc)
    {
        exc.printStackTrace(System.out);
    }
}
于 2013-06-24T14:29:58.527 回答
4

这里的代码片段工作正常，用 Windows 声音测试：

public static void main(String[] args) {
        AePlayWave aw = new AePlayWave( "C:\\WINDOWS\\Media\\tada.wav" );
        aw.start();     
}
于 2010-03-10T13:12:45.917 回答
1

另一种方法是AudioInputStream：

import java.io.File;

import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.Line;
import javax.sound.sampled.LineEvent;
import javax.sound.sampled.LineListener;
import javax.swing.JDialog;
import javax.swing.JFileChooser;

public class CoreJavaSound extends Object implements LineListener {
    File soundFile;

    JDialog playingDialog;

    Clip clip;

    public static void main(String[] args) throws Exception {
        CoreJavaSound s = new CoreJavaSound();
    }

    public CoreJavaSound() throws Exception {
        JFileChooser chooser = new JFileChooser();
        chooser.showOpenDialog(null);
        soundFile = chooser.getSelectedFile();

        System.out.println("Playing " + soundFile.getName());

        Line.Info linfo = new Line.Info(Clip.class);
        Line line = AudioSystem.getLine(linfo);
        clip = (Clip) line;
        clip.addLineListener(this);
        AudioInputStream ais = AudioSystem.getAudioInputStream(soundFile);
        clip.open(ais);
        clip.start();
    }

    public void update(LineEvent le) {
        LineEvent.Type type = le.getType();
        if (type == LineEvent.Type.OPEN) {
            System.out.println("OPEN");
        } else if (type == LineEvent.Type.CLOSE) {
            System.out.println("CLOSE");
            System.exit(0);
        } else if (type == LineEvent.Type.START) {
            System.out.println("START");
            playingDialog.setVisible(true);
        } else if (type == LineEvent.Type.STOP) {
            System.out.println("STOP");
            playingDialog.setVisible(false);
            clip.close();
        }
    }
}
于 2015-06-06T10:17:28.057 回答
1

将播放 WAV 文件的类，在声音播放完毕之前一直阻塞：

class Sound implements Playable {

    private final Path wavPath;
    private final CyclicBarrier barrier = new CyclicBarrier(2);

    Sound(final Path wavPath) {

        this.wavPath = wavPath;
    }

    @Override
    public void play() throws LineUnavailableException, IOException, UnsupportedAudioFileException {

        try (final AudioInputStream audioIn = AudioSystem.getAudioInputStream(wavPath.toFile());
             final Clip clip = AudioSystem.getClip()) {

            listenForEndOf(clip);
            clip.open(audioIn);
            clip.start();
            waitForSoundEnd();
        }
    }

    private void listenForEndOf(final Clip clip) {

        clip.addLineListener(event -> {
            if (event.getType() == LineEvent.Type.STOP) waitOnBarrier();
        });
    }

    private void waitOnBarrier() {

        try {

            barrier.await();
        } catch (final InterruptedException ignored) {
        } catch (final BrokenBarrierException e) {

            throw new RuntimeException(e);
        }
    }

    private void waitForSoundEnd() {

        waitOnBarrier();
    }
}
于 2016-10-28T11:14:16.467 回答
1

没有java反射的解决方案DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat)

Java 反射会降低性能。跑步：java playsound absoluteFilePathTo/file.wav

import javax.sound.sampled.*;
import java.io.*;
public class playsound {

    public static void main (String args[]) throws Exception {
        playSound (args[0]);
    }

    public static void playSound () throws Exception {
        AudioInputStream 
        audioStream = AudioSystem.getAudioInputStream(new File (filename));

        int BUFFER_SIZE = 128000;
        AudioFormat audioFormat = null;
        SourceDataLine sourceLine = null;

        audioFormat = audioStream.getFormat();

        sourceLine = AudioSystem.getSourceDataLine(audioFormat);
        sourceLine.open(audioFormat);
        sourceLine.start();

        int nBytesRead = 0;
        byte[] abData = new byte[BUFFER_SIZE];
        while (nBytesRead != -1) {
            try {
                nBytesRead = 
                audioStream.read(abData, 0, abData.length);
            } catch (IOException e) {
                e.printStackTrace();
            }

            if (nBytesRead >= 0) {
                int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
            }
        }

        sourceLine.drain();
        sourceLine.close();
    }

}
于 2017-08-30T17:07:48.403 回答
0

您也可以通过这种方式使用 AudioStream：

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;

import sun.audio.AudioPlayer;
import sun.audio.AudioStream;

public class AudioWizz extends JPanel implements ActionListener {

    private static final long serialVersionUID = 1L; //you like your cereal and the program likes their "serial"

    static AudioWizz a;
    static JButton playBuddon;
    static JFrame frame;

    public static void main(String arguments[]){

        frame= new JFrame("AudioWizz");
        frame.setSize(300,300);
        frame.setVisible(true);
        a= new AudioWizz();
        playBuddon= new JButton("PUSH ME");
        playBuddon.setBounds(10,10,80,30);
        playBuddon.addActionListener(a);

        frame.add(playBuddon);
        frame.add(a);
    }

    public void actionPerformed(ActionEvent e){ //an eventListener
        if (e.getSource() == playBuddon) {
            try {
                InputStream in = new FileInputStream("*.wav");
                AudioStream sound = new AudioStream(in);
                AudioPlayer.player.start(sound);
            } catch(FileNotFoundException e1) {
                e1.printStackTrace();
            } catch (IOException e1) {
                e1.printStackTrace();
            }
        }
    }

}
于 2016-12-20T20:58:28.017 回答