5

我有一个图（粘贴在下面的示例代码），我试图通过自己的标签添加系列信息。而不是绘制“p1s1”“p1s2”“p3s4”，我想要“治疗1”“治疗2”“治疗3”。我使用levels(series_id) 来获取唯一的系列名称，并使用查找表来获取描述。（我认为这会让它们按照绘制的顺序排列？）我将这些描述放在一个名为treatment_descriptions 的向量中。

从文档中我认为我应该在这里使用比例尺，但我无法弄清楚是哪一个，或者如何做到这一点。类似于： scale_something(name="Treatment Descriptions", breaks=NULL, labels=treatment_descriptions, formatter=NULL) ？但这应该去哪里？

library(ggplot2)

# Create a long data.frame to store data...
growth_series = data.frame ("read_day" = c(0, 3, 9, 0, 3, 9, 0, 2, 8), 
"series_id" = c("p1s1", "p1s1", "p1s1", "p1s2", "p1s2", "p1s2", "p3s4", "p3s4", "p3s4"),
"mean_od" = c(0.6, 0.9, 1.3, 0.3, 0.6, 1.0, 0.2, 0.5, 1.2),
"sd_od" = c(0.1, 0.2, 0.2, 0.1, 0.1, 0.3, 0.04, 0.1, 0.3),
"n_in_stat" = c(8, 8, 8, 8, 7, 5, 8, 7, 2)
)

> # Now gives us some example long form data...
> > growth_series 
>  read_day series_id mean_od sd_od        n_in_stat   
>   1       p1s1     0.6      0.10         8 2       
>   3       p1s1     0.9      0.20         8 3    
>   9       p1s1     1.3      0.20         8 4    
>   0       p1s2     0.3      0.10         8 5    
>   3       p1s2     0.6      0.10         7 6    
>   9       p1s2     1.0      0.30         5 7    
>   0       p3s4     0.2      0.04         8 8    
>   2       p3s4     0.5      0.10         7 9    
>   8       p3s4     1.2      0.30         2 2

# Plot using ggplot...
ggplot(data = growth_series, aes(x = read_day, y = mean_od, group = series_id, color = series_id)) +
geom_line(size = 1.5) +
geom_point(aes(size = n_in_stat)) +
geom_errorbar(aes(ymin = mean_od - sd_od, ymax = mean_od + sd_od), size = 1, width = 0.3) +
xlab("Days") + ylab("Log (O.D. 730 nm)") +
scale_y_log2() +
scale_colour_hue('my legend', breaks = levels(growth_series$series_id), labels=c('t1', 't2', 't3'))
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1 回答 1

6

也许你可以重新标记你的因素？

growth_series$series_id <- factor(
     growth_series$series_id, 
     labels=c('treatment 1', 't2', 't3'))

或者如果你还在寻找 scale_something，它应该是 scale_colour_hue()

... + scale_colour_hue('my legend', 
   breaks = levels(growth_series$series_id), 
   labels=c('t1', 't2', 't3'))
于 2010-02-26T07:11:29.290 回答