3

我编写了一个 SQL 查询，它告诉我前一周最常见的 10 个警报的名称。我编写了一个查询，获取前 10 个警报，并为每个警报提供 YTD 每周总数。

现在，我希望创建一个迷你图面板，显示本周前 10 个警报中每个警报的 YTD 趋势。

我得到了类似于我想要的东西，但我现在需要让它“动态”。即在不硬编码警报名称的情况下使其工作（因为这些名称每周都会随着 SQL 查询而改变）。

如何在不硬编码警报名称的情况下更改下面的 R 代码以使其工作？

levels(spark$Alarm) 是否与此有关？

非常感谢您的建议:-)

Week = c(rep(1:8,2))
Total = rnorm(16,1000,600)
Alarm = c(rep("BELTWEIGHER HIGH HIGH",8), rep("MICROWAVE LHS",8))
spark <- data.frame(Week, Alarm, Total)

s <- ggplot(spark, aes(Week, Total)) +
     facet_grid(Alarm ~ ., scales = "free", as.table = FALSE) +
     opts(
  panel.background = theme_rect(size = 1, colour = "lightgray"),
  panel.grid.major = theme_blank(),
  panel.grid.minor = theme_blank(),
  axis.line = theme_blank(),
  axis.text.x = theme_blank(),
  axis.text.y = theme_blank(),
  axis.title.x = theme_blank(),
  axis.title.y = theme_blank(), 
  axis.ticks = theme_blank(),
  strip.background = theme_blank(),
  strip.text.y = theme_text(size = 7, colour = "red", angle = 90)
 )

s1 <- s  + geom_line(subset = .(Alarm == "BELTWEIGHER HIGH HIGH"))
s2 <- s1 + geom_line(subset = .(Alarm == "MICROWAVE LHS"))
s2
4

1 回答 1

4

好吧，这是一个愚蠢的问题:)

这是显而易见的答案。

Week = c(rep(1:8,2))
Total = rnorm(16,1000,600)
Alarm = c(rep("BELTWEIGHER HIGH HIGH",8), rep("MICROWAVE LHS",8))
spark <- data.frame(Week, Alarm, Total)


s <- ggplot(spark, aes(Week, Total)) +         
     theme(
        panel.background = element_rect(size = 1, colour = "lightgray"),
        panel.grid.major = element_blank(),
        panel.grid.minor = element_blank(),
        axis.line = element_blank(),
        axis.text.x = element_blank(),
        axis.text.y = element_blank(),
        axis.title.x = element_blank(),
        axis.title.y = element_blank(), 
        axis.ticks = element_blank(),
        strip.background = element_blank(),
        strip.text.y = element_blank()
        #strip.text.y = element_text(size = 7, colour = "red", angle = 90)
    )

s + facet_grid(Alarm ~.) + geom_line()
于 2010-02-25T03:05:38.763 回答