11

我可以强制父类调用派生类的函数版本吗?

class Base(object):
    attr1 = ''
    attr2 = ''

    def virtual(self):
        pass               # doesn't do anything in the parent class

    def func(self):
        print "%s, %s" % (self.attr1, self.attr2)
        self.virtual()

以及派生自它的类

class Derived(Base):
    attr1 = 'I am in class Derived'
    attr2 = 'blah blah'

    def virtual(self):
        # do stuff...
        # do stuff...

清除模糊性:

d = Derived()
d.func()         # calls self.virtual() which is Base::virtual(), 
                 #  and I need it to be Derived::virtual()
4

2 回答 2

9

如果您实例化 a Derived(say d = Derived()),则.virtual调用的d.func() 是 is Derived.virtual。如果没有Derived涉及的实例,则没有合适selfDerived.virtual,所以当然不可能调用它。

于 2010-02-19T16:29:07.403 回答
5

这并非不可能——实际上有一种方法可以解决这个问题,而且您不必传入函数或类似的东西。我自己正在研究一个出现这个确切问题的项目。这是解决方案:


class Base(): # no need to explicitly derive object for it to work
    attr1 = 'I am in class Base'
    attr2 = 'halb halb'

    def virtual(self):
        print "Base's Method"

    def func(self):
        print "%s, %s" % (self.attr1, self.attr2)
        self.virtual()

class Derived(Base):
    attr1 = 'I am in class Derived'
    attr2 = 'blah blah'

    def __init__(self):
  # only way I've found so far is to edit the dict like this
        Base.__dict__['_Base_virtual'] = self.virtual

    def virtual(self):
        print "Derived's Method"

if __name__ == '__main__':
    d = Derived()
    d.func()

于 2010-06-28T16:43:50.453 回答