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我正在尝试使用 JMockit 测试静态方法。此方法使用实用程序类静态方法。

当测试运行时，JMockit 抱怨并抛出以下异常：

    测试集：com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest
    -------------------------------------------------- ------------------
    测试运行：1，失败：0，错误：1，跳过：0，经过时间：0.086 秒失败！
    testMakeResourceRequestPositive(com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest) 经过时间：0.085 秒错误！
    mockit.internal.UnexpectedInvocation：com.company.pkg.subpkg.mylib.NetworkUtil#sendHttpRequest(org.apache.http.client.methods.HttpUriRequest requestToSend) 的参数“requestToSend”预期 GET https://localhost HTTP/1.1，得到获取 https://localhost HTTP/1.1
        在 com.company.pkg.subpkg.mylib.NetworkUtil.sendHttpRequest(NetworkUtil.java)
        在 com.company.pkg.subpkg.mylib.serviceaccess.client.ServiceCommunicator.makeResourceRequest(ServiceCommunicator.java:57)
        在 com.company.pkg.subpkg.mylib.test.ServiceCommunicationTest.testMakeResourceRequestPositive(ServiceCommunicationTest.java:79)
        在 sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
        在 java.lang.reflect.Method.invoke(Method.java:606)
        . . .
        . . .

这是导致抛出异常的测试 -



    @RunWith(JUnit4.class)
    public class ServiceCommunicationTest {

        @Mocked
        private NetworkUtil _mockedNetworkUtil;

        @Test
        public void testMakeResourceRequestPositive() throws IOException {

            ResourcesDTO resDto = null;
            final String jsonResponse = JsonResponsesTestUtil.SUCCESSFUL_RESOURCES_RESPONSE;

            final String serviceUrl = "https://localhost";
            final HttpUriRequest requestToSend = new HttpGet(serviceUrl);

            new Expectations() {
                {
                    NetworkUtil.validateStringInput(serviceUrl, "rootUri");

                    NetworkUtil.sendHttpRequest(requestToSend);
                    returns(jsonResponse);
                }
            };

            // Make the actual call …
            try {
                resDto = ServiceCommunicator.makeResourceRequest(serviceUrl);
            } catch (IOException e) {
                Assert.fail("Failed to parse/obtain the Resources DTO: " + e.getMessage());
            }

            Assert.assertNotNull(resDto);
            Assert.assertNotNull(resDto.getSelfUri());
        }
    }

一些令人困惑的事情是预期和实际字符串（如异常中报告的）相同 -

预期 GET https://localhost HTTP/1.1
     得到了 GET https://localhost HTTP/1.1

被测方法在这里——

public static ResourcesDTO makeResourceRequest(String rootUri) throws IOException {

    NetworkUtil.validateStringInput(rootUri, "rootUri");

    // Preparing HTTP Request ...
    HttpUriRequest requestToSend = new HttpGet(rootUri);

    // Headers that needs to be set ...
    requestToSend.addHeader(HttpHeaders.ACCEPT,       MimeConstants.CONTENT_TYPE_STRING);

    // Send Request to Authorization Service ...
    String response = NetworkUtil.sendHttpRequest(requestToSend);

    // Got the response, construct a DTOs out of it ...
    StringReader reader = new StringReader(response);

    // Convert the JSON response to appropriate DTO ...
    ObjectMapper mapper = new ObjectMapper();
    ResourcesDTO resourcesDto = mapper.readValue(reader, ResourcesDTO.class);

    return resourcesDto;
}

上述方法引用的实用程序类是这样的 -



    public final class NetworkUtil {

        // Prevent Instance Creation …
        private NetworkUtil() {
        }

        public  static  ResourcesDTO  makeResourceRequest(String  rootUri)  throws  IOException {

            NetworkUtil.validateStringInput(rootUri, "rootUri");

            // Preparing HTTP Request ...
            HttpUriRequest requestToSend = new HttpGet(rootUri);

            // Headers that needs to be set ...
            requestToSend.addHeader(HttpHeaders.ACCEPT,   MimeConstants.CONTENT_TYPE_STRING);

            // Send Request to the Server ...
            String response = NetworkUtil.sendHttpRequest(requestToSend);

            // Got the response, construct a DTOs out of it ...
            StringReader reader = new StringReader(response);

            // Convert the JSON response to appropriate DTO ...
            ObjectMapper mapper = new ObjectMapper();
            ResourcesDTO resourcesDto = mapper.readValue(reader, ResourcesDTO.class);

            return resourcesDto;
        }
    }

谁能看到这里发生了什么？

4

1 回答 1

4

最后，我能够确定这个 Unexpected Invocation 异常的原因。

NetworkUtil.sendHttpRequest((HttpUriRequest) any);
returns(jsonResponse);

如上所示，我在期望块中更改了返回之前的行。现在我告诉 JMockit，任何HttpUriRequest 类型的对象都是可以接受的，而不是传递 HttpUriRequest 类型的对象。

我相信，JMockit 对模拟 API 调用的参数执行 equals()。这里的问题可能是 HttpUriRequest 没有实现自己的 equals() 方法，而是继承自 Object。这意味着它本质上是在做一个 object1 == object2。

于 2014-04-10T15:38:53.460 回答