3

我正在尝试使 php 中的点对点应用程序以与 Skype 工作方式相同的方式工作。它适用于内部地址,但是当我尝试将数据发送到我的外部地址时,消息永远不会到达那里。显然我错过了一些地址转换,但我不知道如何使用 PHP 套接字来做到这一点。可能吗?

这是我目前接收消息的代码,我首先运行它以等待一些消息:

<?php
$socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create socket: " . socket_strerror(socket_last_error($socket)));
socket_bind($socket, "0.0.0.0", 100) or die("Could not bind socket: " . socket_strerror(socket_last_error($socket)));

$ret = "";
$from_ip = "";
$from_port = 0;


echo "waiting...\n";
socket_recvfrom($socket, $ret, 6, 0, $from_ip, $from_port);

var_dump($ret, $from_ip, $from_port);

socket_close($socket);

然后当它等待时,我运行这段代码来发送一条消息:

<?php
$socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create socket: " . socket_strerror(socket_last_error($socket)));


$to_ip = "externalip"; //works with internal "127.0.0.1";
$to_port = 100;
$message = "hello!";

socket_sendto($socket, $message, strlen($message), 0, $to_ip, $to_port);
echo "sent\n";

socket_close($socket);

但它发送并退出,但第一个脚本仍在等待......现在已经有一段时间了,有人可以帮我吗?

- 编辑 -

好的,所以我已经实现了一个 stun 服务器并为它设置了端口转发,如下所示:

<?php

echo "-- STUN SERVER --\n";

$socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create socket: " . socket_strerror(socket_last_error($socket)));
socket_bind($socket, "0.0.0.0", 5104) or die("Could not bind socket: " . socket_strerror(socket_last_error($socket)));


do {
    $ret = "";
    $from = "";
    $port = 0;

    echo "waiting...\n";
    socket_recvfrom($socket, $ret, 6, 0, $from, $port);

    echo "received: $ret\n";

    $message = $from.":".$port;
    socket_sendto($socket, $message, strlen($message), 0, $from, $port);
    echo "sent: $message\n\n";
}
while (true);

并更改了我的第一个脚本以从 stun 服务器获取其 ip/端口:

<?php
$socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create socket: " . socket_strerror(socket_last_error($socket)));
socket_bind($socket, "0.0.0.0", 100) or die("Could not bind socket: " . socket_strerror(socket_last_error($socket)));

$ret = "";
$from = "";
$port = 0;


echo "sending info to stun server...\n";
$to_ip = "stunip";
$to_port = 5104;
$message = "get_ip";
socket_sendto($socket, $message, strlen($message), 0, $to_ip, $to_port);

echo "waiting for stun...\n";
$stuninfo = "";
socket_recvfrom($socket, $stuninfo, 25, 0, $from, $port);

var_dump($stuninfo); // i use this info in my second script


echo "waiting...\n";
socket_recvfrom($socket, $ret, 6, 0, $from, $port);

var_dump($ret, $from, $port);

socket_close($socket);

它可以从 stun 服务器获取信息并等待另一个连接,但是当我在我的第二个脚本中使用该信息时,第一个脚本仍然没有收到任何消息.. 还有我遗漏的另一个步骤吗?

4

0 回答 0