怎么样 :
> DT[, mean(b), keyby=cut(a,quantile(a,probs=seq(.1,.9,.1)))]
cut V1
1: NA -0.31359818
2: (-1.05,-0.614] -0.14103182
3: (-0.614,-0.375] -0.33474492
4: (-0.375,-0.0767] 0.20827735
5: (-0.0767,0.114] 0.14890251
6: (0.114,0.377] 0.16685304
7: (0.377,0.581] 0.07086979
8: (0.581,0.771] 0.17950572
9: (0.771,1.18] -0.04951607
为了看看那个 NA(无论如何都要检查结果),我接下来做了:
> DT[, list(mean(b),.N,list(a)), keyby=cut(a,quantile(a,probs=seq(.1,.9,.1)))]
cut V1 N V3
1: NA -0.31359818 20 1.59528080213779,1.51178116845085,-2.2146998871775,-1.98935169586337,-1.47075238389927,1.35867955152904,
2: (-1.05,-0.614] -0.14103182 10 -0.626453810742332,-0.835628612410047,-0.820468384118015,-0.621240580541804,-0.68875569454952,-0.70749515696212,
3: (-0.614,-0.375] -0.33474492 10 -0.47815005510862,-0.41499456329968,-0.394289953710349,-0.612026393250771,-0.443291873218433,-0.589520946188072,
4: (-0.375,-0.0767] 0.20827735 10 -0.305388387156356,-0.155795506705329,-0.102787727342996,-0.164523596253587,-0.253361680136508,-0.112346212150228,
5: (-0.0767,0.114] 0.14890251 10 -0.0449336090152309,-0.0161902630989461,0.0745649833651906,-0.0561287395290008,-0.0538050405829051,-0.0593133967111857,
6: (0.114,0.377] 0.16685304 10 0.183643324222082,0.329507771815361,0.36458196213683,0.341119691424425,0.188792299514343,0.153253338211898,
7: (0.377,0.581] 0.07086979 10 0.487429052428485,0.575781351653492,0.389843236411431,0.417941560199702,0.387671611559369,0.556663198673657,
8: (0.581,0.771] 0.17950572 10 0.738324705129217,0.593901321217509,0.61982574789471,0.763175748457544,0.696963375404737,0.768532924515416,
9: (0.771,1.18] -0.04951607 10 1.12493091814311,0.943836210685299,0.821221195098089,0.918977371608218,0.782136300731067,1.10002537198388,
旁白:我已经返回了一list
列(每个单元格本身就是一个向量),以便快速查看进入垃圾箱的值,只是为了检查。data.table
打印时显示逗号(并且每个单元格仅显示前 6 个项目),但实际上每个单元格V3
都有一个数字向量。
所以第一个和最后一个之外的值break
被一起编码为NA。对我来说,如何告诉cut
不要那样做并不明显。所以我只是添加了 -Inf 和 +Inf :
> DT[,list(mean(b),.N),keyby=cut(a,c(-Inf,quantile(a,probs=seq(.1,.9,.1)),+Inf))]
cut V1 N
1: (-Inf,-1.05] -0.16938368 10
2: (-1.05,-0.614] -0.14103182 10
3: (-0.614,-0.375] -0.33474492 10
4: (-0.375,-0.0767] 0.20827735 10
5: (-0.0767,0.114] 0.14890251 10
6: (0.114,0.377] 0.16685304 10
7: (0.377,0.581] 0.07086979 10
8: (0.581,0.771] 0.17950572 10
9: (0.771,1.18] -0.04951607 10
10: (1.18, Inf] -0.45781268 10
这样更好。或者:
> DT[, list(mean(b),.N), keyby=cut(a,quantile(a,probs=seq(0,1,.1)),include=TRUE)]
cut V1 N
1: [-2.21,-1.05] -0.16938368 10
2: (-1.05,-0.614] -0.14103182 10
3: (-0.614,-0.375] -0.33474492 10
4: (-0.375,-0.0767] 0.20827735 10
5: (-0.0767,0.114] 0.14890251 10
6: (0.114,0.377] 0.16685304 10
7: (0.377,0.581] 0.07086979 10
8: (0.581,0.771] 0.17950572 10
9: (0.771,1.18] -0.04951607 10
10: (1.18,2.4] -0.45781268 10
这样您就可以看到最小值和最大值是什么,而不是显示 -Inf 和 +Inf。请注意,您需要传递include=TRUE
给,cut
否则将返回 11 个垃圾箱,第一个垃圾箱中只有 1 个。