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在 Solr 中提升静态值的最佳方法是什么3.6.2？

每个文档都有一个（KeywordTokenized）source值（信息来源），我想表达一些比其他更重要。如果有帮助，则可以进行完整的内容控制。

http://localhost:8080/solr/index/select?fl=source,score
  &defType=edismax
  &qf=title^4
  &q=qux
  &bq=source:foo^10
  &bq=source:bar^14

不幸的是，加法增强查询几乎没有效果。解析后的查询看起来像这样（qux 被提取为 qu）

+DisjunctionMaxQuery(((title:qux qu)^4.0))) source:foo^10.0 source:bar^14.0

前两个结果的调试查询并没有显着尊重bq=source:foo^10

5.366351 = (MATCH) sum of: 5.366351 = (MATCH) sum of: 2.067319 = (MATCH) weight(title:qux in 4472), product of: 0.5513683 = queryWeight(title:qux), product of: 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.073526874 = queryNorm 3.7494338 = (MATCH) fieldWeight(title:qux in 4472), product of: 1.0 = tf(termFreq(title:qux)=1) 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.5 = fieldNorm(field=title, doc=4472) 3.299032 = (MATCH) weight(title:qu in 4472), product of: 0.69651634 = queryWeight(title:qu), product of: 9.472949 = idf(docFreq=4, maxDocs=23918) 0.073526874 = queryNorm 4.7364745 = (MATCH) fieldWeight(title:qu in 4472), product of: 1.0 = tf(termFreq(title:qu)=1) 9.472949 = idf(docFreq=4, maxDocs=23918) 0.5 = fieldNorm(field=title, doc=4472)

5.281746 = (MATCH) sum of: 4.134638 = (MATCH) sum of: 4.134638 = (MATCH) weight(title:qux in 4402), product of: 0.5513683 = queryWeight(title:qux), product of: 7.4988675 = idf(docFreq=35, maxDocs=23918) 0.073526874 = queryNorm 7.4988675 = (MATCH) fieldWeight(title:qux in 4402), product of: 1.0 = tf(termFreq(title:qux)=1) 7.4988675 = idf(docFreq=35, maxDocs=23918) 1.0 = fieldNorm(field=title, doc=4402) 1.147108 = (MATCH) weight(source:foo^10.0 in 4402), product of: 0.45919293 = queryWeight(source:foo^10.0), product of: 10.0 = boost 2.4980958 = idf(docFreq=5346, maxDocs=23918) 0.018381719 = queryNorm 2.4980958 = (MATCH) fieldWeight(source:foo in 4402), product of: 1.0 = tf(termFreq(source:foo)=1) 2.4980958 = idf(docFreq=5346, maxDocs=23918) 1.0 = fieldNorm(field=source, doc=4402)

有趣的是，尽管字段中有值，但第一个结果没有 queryWeightfor 。由于词形还原也有点不同sourcesourcefieldNorm

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1 回答 1

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该问题很可能是由于 queryNorm。见： http: //lucene.472066.n3.nabble.com/QueryNorm-and-FieldNorm-td1992964.html

只要您不根据不同查询的分数比较结果，单个搜索中的相关性排序应该没问题。

于 2014-03-13T21:18:24.310 回答