给出了这两个函数。
def split_on_separators(original, separators):
""" (str, str) -> list of str
Return a list of non-empty, non-blank strings from the original string
determined by splitting the string on any of the separators.
separators is a string of single-character separators.
>>> split_on_separators("Hooray! Finally, we're done.", "!,")
['Hooray', ' Finally', " we're done."]
"""
# To do: Complete this function's body to meet its specification.
# You are not required to keep the two lines below but you may find
# them helpful. (Hint)
for i in separators:
original = original.replace(i,"<*)))>{")
ret = original.split("<*)))>{")
return ret
def clean_up(s):
""" (str) -> str
Return a new string based on s in which all letters have been
converted to lowercase and punctuation characters have been stripped
from both ends. Inner punctuation is left untouched.
>>> clean_up('Happy Birthday!!!')
'happy birthday'
>>> clean_up("-> It's on your left-hand side.")
" it's on your left-hand side"
"""
punctuation = """!"',;:.-?)([]<>*#\n\t\r"""
result = s.lower().strip(punctuation)
return result
我应该返回每个句子的平均短语数。这是我写的函数
def avg_sentence_complexity(text):
""" (list of str) -> float
Return the average number of phrases per sentence.
A sentence is defined as a non-empty string of non-terminating
punctuation surrounded by terminating punctuation
or beginning or end of file. Terminating punctuation is defined as !?.
Phrases are substrings of sentences, separated by one or more of the
following delimiters ,;:
>>> text = ['The time has come, the Walrus said\n',
'To talk of many things: of shoes - and ships - and sealing wax,\n',
'Of cabbages; and kings.\n',
'And why the sea is boiling hot;\n',
'and whether pigs have wings.\n']
>>> avg_sentence_complexity(text)
3.5
"""
huge_str = ''
clean_sentences = []
for lines in text:
huge_str += lines
list_of_sentences = split_on_separators(huge_str, '?!.')
for strings in list_of_sentences:
cleaned = clean_up(strings)
clean_sentences.append(cleaned)
if '' in clean_sentences:
clean_sentences.remove('')
num_sentences = len(clean_sentences)
large = ''
for phrases in text:
large += phrases
list_of_phrases = split_on_separators(large, ',;:')
num_phrases = len(list_of_phrases)
asc = num_phrases / num_sentences
return asc
这只会给我 3.0，即总短语除以总句子。我的问题是如何计算（第一句中的总短语）/（总句子）+（第二句中的总短语）/（总句子）+ ...