sql - Oracle：具有所有约束的表

Question

我正在尝试创建一个 select 语句，它允许我对所有外键进行概览。它应该如下所示：

表 1 | FK_值 | 表 2 | FK_值

我发现“user_constraints”表必须有一种方法，但我需要一些帮助。

Answer 1

我认为你需要这个：

SELECT a.table_name, a.column_name, a.constraint_name, c.owner, 
       -- referenced pk
       c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk
  FROM all_cons_columns a
  JOIN all_constraints c ON a.owner = c.owner
                        AND a.constraint_name = c.constraint_name
  JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
                           AND c.r_constraint_name = c_pk.constraint_name
 WHERE c.constraint_type = 'R'
   AND a.table_name = :TableName

资料来源：stackoverflow.com/questions/1729996/list-of-foreign-keys-and-the-tables-they-reference

Answer 2

这在 SQL2008 中对我有用（没有 2005）

要获取引用表和列名的列表...

select t.name as TableWithForeignKey, fk.constraint_column_id as FK_PartNo , c.name as ForeignKeyColumn 
from sys.foreign_key_columns as fk
inner join sys.tables as t on fk.parent_object_id = t.object_id
inner join sys.columns as c on fk.parent_object_id = c.object_id and fk.parent_column_id = c.column_id
where fk.referenced_object_id = (select object_id from sys.tables where name = 'TableOthersForeignKeyInto')
order by TableWithForeignKey, FK_PartNo