我有三个日期:(1)previousDate(2)currentDate(3)nextDate,我想检查currentDate 是否晚于上一个日期并且早于nextDate。我怎么做?
问问题
8884 次
6 回答
8
NSDateFormatter *df= [[NSDateFormatter alloc] init];
[df setDateFormat:@"yyyy-MM-dd"];
NSDate *dt1 = [[NSDate alloc] init];
NSDate *dt2 = [[NSDate alloc] init];
dt1=[df dateFromString:@"2011-02-25"];
dt2=[df dateFromString:@"2011-03-25"];
NSComparisonResult result = [dt1 compare:dt2];
switch (result)
{
case NSOrderedAscending: NSLog(@"%@ is greater than %@", dt2, dt1); break;
case NSOrderedDescending: NSLog(@"%@ is less %@", dt2, dt1); break;
case NSOrderedSame: NSLog(@"%@ is equal to %@", dt2, dt1); break;
default: NSLog(@"erorr dates %@, %@", dt2, dt1); break;
}
于 2011-04-20T10:39:08.230 回答
6
我想你正在使用NSDate类。
您可以使用isEqualToDate比较两个 NSDate 对象。并且检查 currentdate 的earlyDate和laterDate大于上一个日期并且小于下一个日期。
于 2010-02-04T12:14:25.130 回答
4
我只是用它来检查它:
if ([[currentDate laterDate:nextDate] isEqualToDate:nextDate]) {
NSLog(@"currentDate is earlier than nextDate");
}
if ([[currentDate laterDate:previousDate] isEqualToDate:currentDate]) {
NSLog(@"currentDate is later then previousDate");
}
对我来说很好!感谢@Luca Matteis 提示“laterDate:”
于 2013-02-01T17:44:47.173 回答
2
我们可以在 swift 5.0 中轻松比较两个日期
switch dateOld.compare(dateNew) {
case .orderedAscending:
// Put your code for greater
break
case .orderedDescending:
// Put your code less
break;
case .orderedSame:
// Put your code for equal
break
}
于 2019-08-02T06:16:46.150 回答
0
NSDate 对象还实现了有据可查的 -compare: 方法。
于 2010-02-04T12:25:12.923 回答
0
只需使用以下compare
消息进行两次比较NSDate
:
if ([previousDate compare:currentDate] == NSOrderedAscending &&
[nextDate compare:currentDate] == NSOrderedDescending) {
NSLog(@"current date is in between previous and next date (non-inclusive)");
}
于 2014-07-04T07:40:25.550 回答