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如何使用 PHP/GMP 计算整数的第 n 个根?

虽然我gmp_root(a, nth)PHP 源代码中找到了一个调用的函数,但似乎这个函数还没有在任何版本中发布*:http: //3v4l.org/8FjU7

*) 5.6.0alpha2 是撰写本文时的最新版本

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1 回答 1

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原始来源:在 PHP 中使用 bcmath 计算 Nth root - 感谢HamZa

我重写了代码以使用 GMP 而不是 BCMath:

function gmp_nth_root($num, $n) {
    if ($n < 1) return 0; // we want positive exponents 
    if ($num <= 0) return 0; // we want positive numbers 
    if ($num < 2) return 1; // n-th root of 1 or 2 give 1 

    // g is our guess number 
    $g = 2; 

    // while (g^n < num) g=g*2 
    while (gmp_cmp(gmp_pow($g, $n), $num) < 0) { 
        $g = gmp_mul($g, 2); 
    } 
    // if (g^n==num) num is a power of 2, we're lucky, end of job 
    if (gmp_cmp(gmp_pow($g, $n), $num) == 0) { 
        return $g; 
    } 

    // if we're here num wasn't a power of 2 :( 
    $og = $g; // og means original guess and here is our upper bound 
    $g = gmp_div($g, 2); // g is set to be our lower bound 
    $step = gmp_div(gmp_sub($og, $g), 2); // step is the half of upper bound - lower bound 
    $g = gmp_add($g, $step); // we start at lower bound + step , basically in the middle of our interval 

    // while step != 1 

    while (gmp_cmp($step, 1) > 0) { 
        $guess = gmp_pow($g, $n); 
        $step = gmp_div($step, 2); 
        $comp = gmp_cmp($guess, $num); // compare our guess with real number 
        if ($comp < 0) { // if guess is lower we add the new step 
            $g = gmp_add($g, $step); 
        } else if ($comp == 1) { // if guess is higher we sub the new step 
            $g = gmp_sub($g, $step); 
        } else { // if guess is exactly the num we're done, we return the value 
            return $g; 
        } 
    } 

    // whatever happened, g is the closest guess we can make so return it 
    return $g; 
}
于 2014-02-22T11:16:33.830 回答