12

我想通过单击弹出窗口外部或后退按钮来关闭弹出窗口，但是当单击后退按钮时，我的应用程序退出，而不是退出应用程序，我想关闭弹出窗口。

这是我的代码，

ivmainmenu.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View v) {
        // TODO Auto-generated method stub

        LayoutInflater layoutInflater = (LayoutInflater)getBaseContext()
                .getSystemService(LAYOUT_INFLATER_SERVICE);  
        View popupView = layoutInflater.inflate(R.layout.popupwindow, null);  
        final PopupWindow popupWindow = new PopupWindow(popupView,LayoutParams.FILL_PARENT,
                LayoutParams.WRAP_CONTENT);  
        popupWindow.showAsDropDown(ivmainmenu, 0,14);
        popupView.setPadding(0, 0, 0, 10);
        popupWindow.showAsDropDown(ivmainmenu);

        popupWindow.setBackgroundDrawable(new BitmapDrawable());
        popupWindow.setOutsideTouchable(false);

        TextView tvpopupwork = (TextView)popupView.findViewById(R.id.tvpopupwork);
        TextView tvpopupabout = (TextView)popupView.findViewById(R.id.tvpopupabout);
        TextView tvpopupservices = (TextView)popupView.findViewById(R.id.tvpopupservices);
        TextView tvpopupcontact = (TextView)popupView.findViewById(R.id.tvpopupcontact);

        Typeface typeFace2 =  Typeface.createFromAsset(getAssets(),"fonts/arboriaboldregular.ttf");
        tvpopupwork.setTypeface(typeFace2);
        tvpopupabout.setTypeface(typeFace2);
        tvpopupservices.setTypeface(typeFace2);
        tvpopupcontact.setTypeface(typeFace2);

        tvpopupwork.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                Intent intent = new Intent(Home.this,Ourwork.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intent);
            }
        });

        tvpopupabout.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub
                Intent intent = new Intent(Home.this,Aboutus.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intent);  
            }
        });

        tvpopupservices.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub

                Intent intent = new Intent(Home.this,Services.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intent);
            }
        });

        tvpopupcontact.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub

                Intent intent = new Intent(Home.this,Contact.class);
                intent.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intent);
            }
        });

        ivmainmenu.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                // TODO Auto-generated method stub

                popupWindow.dismiss();
            }
        });
    }
});

它给了我想要的结果，但是当我关闭菜单时它不会再次打开，我想再次打开它，我该怎么办？谢谢你。

4

6 回答 6

25

代替

popupWindow.setOutsideTouchable(false);

有了这个

popupWindow.setOutsideTouchable(true);
popupWindow.setFocusable(true);
于 2014-02-20T05:17:01.763 回答
7

维护全局参考PopUpWindow并覆盖onBackPressed()...

@Override
public void onBackPressed() {
    if (popupWindow != null && popupWindow.isShowing()) {
        popupWindow.dismiss();
    } else {
        super.onBackPressed();
    }
}

以同样的方式解雇Button...

    ivmainmenu.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            if(popupWindow != null && popupWindow.isShowing()) {
                popupWindow.dismiss();
                popupWindow = null;
            } else {
                // show pop up now
            }
        }
    });
于 2014-02-20T05:18:19.643 回答
2

请写onBackPressed(）并有以下代码

if(popup!=null){
   //dismiss the popup
   popup.dismiss();
   //make popup null again
   popup=null;
}
于 2014-02-20T05:19:03.593 回答
1

试试这个方法：实现onBackPressed()并添加

if(popup!=null) {
    popup.dismiss();
    popup=null;
}

并设置PopWindow如下：

popup.setOutsideTouchable(true);
于 2014-02-20T05:17:27.867 回答
0

您可以在代码中覆盖 onBackPressed() 回调并检查您的弹出窗口是否已经显示（然后将其关闭），否则您调用 super 以获得正常行为。

于 2014-02-20T05:18:14.677 回答
0

尝试这个..

用作PopupWindow popupWindow全局变量

利用popup.setOutsideTouchable(true);

@Override
public void onBackPressed() {
    if (popupWindow != null) {
        if (popupWindow.isShowing()) {
            popupWindow.dismiss();
        }
    } else {
        finish();
    }
}
于 2014-02-20T05:19:03.807 回答