0

遇到的问题

当我创建一个带有子集合的瞬态实例时,一切都会被持久化。

另外,如果我更新其中一个子对象的实例,则在我保存父对象时它不会更新。

我实际上正在使用cascade="all"

Problem reproduction

当我加载了所有客户事件并更改了发票时,就会出现问题,尽管我总是使用相同的ISession.

var repository = new CustomerRepository(session);
var customers = repository.GetAll();
var customer = customers.Where(c => c.Name == "Stack Overflow").FirstOrDefault();           
customer.Invoices
    .Where(i => i.Number == "1234")
    .Approve(WindowsIdentity.GetCurrent().Name);    
repository.Save(customer);

逐步调试清楚地显示repository.Save()正在执行的方法,并且更改不会显示在底层数据库中。

可以直接针对数据库表进行更新,因此没有任何约束会导致数据库端更新失败。

附上一些代码以防万一。

Customer.hbm.xml

<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" 
                   namespace="MyProject.Model" 
                   assembly="MyProject">
    <class name="Customer" table="AC_CUST" schema="AC">
      <id name="Id" column="AC_CUST_ID" type="Int32" unsaved-value="0">
        <generator class="sequence-identity">
          <param name="sequence">AC_CUST_ID_SEQ</param>
          <param name="schema">AC</param>
        </generator>
      </id>
      <property name="Name" column="AC_CUST_NAME" type="String" 
                not-null="true" />
      <property name="PhoneNumber" column="AC_CUST_PHNUM" type="Int64" 
                not-null="true" />
      <bag name="Invoices" table="ESO_RAPP_ACCES_INFO_DSQ" schema="AC" 
           fetch="join" lazy="true" inverse="true" cascade="all">
        <key column="AC_CUST_ID" foreign-key="AC_CUST_INV_FK" />
        <one-to-many class="Invoice" />
      </bag>
    </class>
</hibernate-mapping>

Customer

public class Customer {
    public Customer() { Invoices = new List<Invoice>(); }

    public virtual int Id { get; proected set; }
    public virtual IList<Invoice> Invoices { get; protected set; }
    public virtual string Name { get; set; }
    public virtual string PhoneNumber { get; set; }
}

Invoice.hbm.xml

<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" 
                   namespace="MyProject.Model" 
                   assembly="MyProject">
    <class name="Invoice" table="AC_INV" schema="AC">
      <id name="Id" column="AC_INV_ID" type="Int32" unsaved-value="0">
        <generator class="sequence-identity">
          <param name="sequence">AC_INV_ID_SEQ</param>
          <param name="schema">AC</param>
        </generator>
      </id>
      <property name="Approved" column="AC_INV_APPRD" type="DateTime" 
                not-null="false" />
      <property name="Approver" column="AC_INV_APPRR" type="String" length="15" 
                not-null="false" />
      <property name="Number" column="AC_INV_NUMBR" type="String" length="15" 
                not-null="true" />
      <property name="Produced" column="AC_INV_PROD" type="DateTime" 
                not-null="false" />
      <many-to-one class="Customer" column="AC_CUST_ID" />
    </class>
</hibernate-mapping>

Invoice

public class Invoice {
    public Invoice() { 
        Items = new List<Item>(); 
        Produced = DateTime.Now;
    }

    public virtual DateTime? Approved { get; protected set; }
    public virtual string Approver { get; protected set; }
    public virtual Customer Customer { get; set; }
    public virtual int Id { get; proected set; }
    public virtual string Number { get; set; }
    public virtual DateTime? Produced { get; set; }

    public virtual void Approve(string approver) {
        Approved = DateTime.Now;
        Approver = approver;
    }

    public virtual void Reject() { Produced = null; }
}

CustomerRepository

public class CustomerRepository {
    public CustomerRepository(ISession session) { Session = session; }

    public ISession Session { get; protected set; }

    public Customer Save(Customer instance) {
        Session.SaveOrUpdate(instance);
        return Instance;
    }
}

相关文章

任何帮助表示赞赏。

4

1 回答 1

0

不要忘记参加Flush()您的会议!

NHibernate 跟踪会话生命周期中的所有更改,这些更改应该只存在于表单(桌面)或页面(Web)。

由于会话知道所有更改,它不一定将更改提交到底层数据库。相反,它将所有更改记录到字典中,然后当通过调用刷新它时ISession.Flush(),您实际上要求会话永久提交更改。

所以解决方案应该是:

repository.Save(customer);
session.Flush();

或者您也可以Commit()在您的存储库中编写一个方法,该方法将Flush()在调用时进行会话。

repository.Save(customer);
repository.Commit();

您的存储库将如下所示:

// Assuming you stock your session in the `Session` property.
public void Commit() { Session.Flush(); }

就这样!

于 2014-02-20T01:32:45.330 回答