我想知道是否有任何功能可以将输出重定向t.test
到LaTeX
。像这样的东西
library(xtable)
xtable(t.test(extra ~ group, data = sleep))
我想知道是否有任何功能可以将输出重定向t.test
到LaTeX
。像这样的东西
library(xtable)
xtable(t.test(extra ~ group, data = sleep))
这可以解决问题。
library(schoRsch)
library(xtable)
T.Test <- t.test(extra ~ group, data = sleep)
xtable(
t_out(toutput=T.Test, n.equal = TRUE, welch.df.exact = TRUE, welch.n = NA,
d.corr = TRUE, print = TRUE)
)
Test Results
1 Welch Two Sample t-test: t(17.78) = -1.86, p = .079, d = NA
% latex table generated in R 3.1.1 by xtable 1.7-3 package
% Mon Aug 25 21:01:13 2014
\begin{table}[ht]
\centering
\begin{tabular}{rll}
\hline
& Test & Results \\
\hline
1 & Welch Two Sample t-test: & t(17.78) = -1.86, p = .079, d = NA \\
\hline
\end{tabular}
\end{table}
您可以使用带有knitr::kable
函数的简单 S3 方法:
as.data.frame.htest <- function(x) {
x <- unclass(x)
names <- c("statistic", "estimate", "parameter", "p.value")
x <- x[names]
x <- x[!sapply(x, is.null)]
for (i in seq_along(x)) {
if (!is.null(names(x[[i]])))
names(x)[i] <- names(x[[i]])
}
as.data.frame(x, stringsAsFactors = FALSE)
}
knitr::kable(t.test(extra ~ group, data = sleep), format = "latex")
注意:有关类结构str(t.test(extra ~ group, data = sleep))
的更多详细信息,请参阅 。htest