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有人可以帮忙计算这个 PIVOT 表底部的总行吗?

    select *, [Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5] as [Total]
from 
        (Select [id], [drug], [Diagnosis]
            from DrugDiagnosis
        ) as ptp
        pivot 
            (count(id) 
                for drug 
                in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
            ) as PivotTable

我知道我可以使用 UNION 来完成,并有一个单独的查询来计算总数,但这会使数据库的命中率加倍。

我找到了使用 ROLLUP 和 CUBE 的示例,但这些都是不推荐使用的功能,所以我不想使用它们。

任何其他想法,也许是分组?

4

1 回答 1

1

您可以使用GROUPING SETS获取总计行:

select isnull(diagnosis, 'Total') Diagnosis, 
  sum([Drug1]) Drug1, sum([Drug2]) Drug2, 
  sum([Drug3]) Drug3, sum([Drug4]) Drug4, 
  sum([Drug5]) Drug5,
  sum([Drug1] + [Drug2] + [Drug3] + [Drug4] + [Drug5]) as [Total]
from 
(
  Select [id], [drug], [Diagnosis]
  from DrugDiagnosis
) as ptp
pivot 
(
  count(id) 
  for drug in ([Drug1], [Drug2], [Drug3], [Drug4], [Drug5]) 
) as PivotTable
group by grouping sets((diagnosis), ());

请参阅带有演示的 SQL Fiddle

于 2014-01-30T17:31:45.543 回答