2

我试图通过匹配对象标签来找到与一个对象相关的对象。我已经构建了一个 mysql 查询，它将通过计算匹配标签来返回最匹配的对象。

我是学说（1.2）的新手，所以我想知道是否有人可以帮助我走上正确的轨道，修改我的架构并创建 DQL 查询？最大的问题是，我猜这两个标签集在我的 schema.yml 中彼此不相关。

架构.yml：

Object:
  columns:
    name:
  relations:
    Tags: { foreignAlias: Objects, class: Tag, refClass: Tagset}

Tagset:
  columns:
    object_id: {type: integer, primary: true, notnull: true}
    tag_id: { type: integer, primary: true, notnull: true }
  relations:
    Object: { foreignAlias: Tagsets }
    Tag: { foreignAlias: Tagsets }

Tag:
  columns:
    name: { type: string(255), notnull: true }
    Object: { foreignAlias: Tags, class: Object, refClass: Tagset}

这是使用上述模式的 mysql 查询：

SELECT object.name, COUNT(*) AS tag_count
FROM tagset T1
INNER JOIN tagset T2
    ON T1.tag_id = T2.tag_id AND T1.object_id != T2.object_id
INNER JOIN object
    ON T2.object_id = object.id
WHERE T1.object_id = 2
GROUP BY T2.object_id
ORDER BY COUNT(*) DESC
4

2 回答 2

2

您也可以使用子查询。像这样的东西：

$object_id = 2;

Doctrine::getTable('Tagset')->createQuery('t')
  ->select('t.tag_id, o.id, o.name, COUNT(t.tag_id) AS tag_count')
  ->innerJoin('t.Object o WITH o.id != ?', $object_id)
  ->where('t.tag_id IN (SELECT t.tag_id FROM Tagset t WHERE t.object_id = ?)', $object_id)
  ->groupBy('t.object_id')
于 2010-01-27T16:10:11.120 回答
1

解决方案：

$q = new Doctrine_RawSql();
    $this->related_objects = $q->
            select('{o.name}')->
            from('tagset t1 JOIN tagset t2 ON t1.tag_id = t2.tag_id AND t1.object_id != t2.object_id JOIN object o ON t2.object_id = o.id')->
            addComponent('o','Object o')->
            where('t1.object_id = ?', $this->object->id)->
            groupBy('t2.object_id')->
            orderBy('COUNT(*) DESC')->
            execute();
于 2010-01-27T11:50:34.803 回答