我需要一个扩展方法来遍历我的 Silverlight 页面上的所有文本框。假设我总是使用网格布局,那么我有:
public static IEnumerable<UIElement> Traverse(this UIElementCollection source, Func<Grid, UIElementCollection> fnRecurse)
{
foreach (UIElement item in source)
{
yield return item;
var g = source.OfType<Grid>();
foreach (Grid itemsub in g)
{
var t = fnRecurse(itemsub);
t.Traverse(fnRecurse);
yield return itemsub;
};
}
}
现在,我可以这样称呼它:
baseLayout.Children.Traverse(x => x.Children ).OfType<TextBox>().ForEach(
w =>
{
//Text Box Extension Method, clears the text
w.reset();
});
这永远不会触发。我相信是 OfType 无法区分 UI 元素。
我该怎么做?我想展平视觉树然后循环。不仅仅是文本框,而是得到所有我想要的东西。我是在错误的地方屈服还是过于频繁?
编辑:
当前代码
public static IEnumerable<UIElement> Traverse(this UIElementCollection source, Func<Grid, UIElementCollection> fnRecurse)
{
foreach (UIElement item in source)
{
source.OfType<Grid>().Select(x => x.Children).ForEach(v => Traverse(v, fnRecurse));
yield return item;
}
}
网格是
<Grid x:Name="LayoutRoot">
<Grid.RowDefinitions>
<RowDefinition Height="42"/>
<RowDefinition Height="42"/>
<RowDefinition Height="45"/>
<RowDefinition Height="43"/>
<RowDefinition Height="47"/>
<RowDefinition Height="46"/>
<RowDefinition/>
<RowDefinition Height="67"/>
</Grid.RowDefinitions>
<Button x:Name="saveAddressButton" Height="24" HorizontalAlignment="Left" Margin="8,0,0,8" VerticalAlignment="Bottom" Width="135" Content="Save and Add More" Click="saveClick" Style="{StaticResource SaveButton}" Foreground="White" Grid.Row="7"/>
<Button x:Name="saveAddressButton_Copy" Height="24" HorizontalAlignment="Right" Margin="0,0,8,8" VerticalAlignment="Bottom" Width="81" Content="Clear" Click="clearClick" Style="{StaticResource SaveButton}" Foreground="White" Grid.Row="7"/>
<Grid Height="30" VerticalAlignment="Top" Margin="8,9,8,0">
<TextBlock Margin="8,0,0,0" Text="AddressLine1" FontSize="16" Foreground="White" HorizontalAlignment="Left" Width="121"/>
<TextBox x:Name="inputAddressLine1" TextWrapping="Wrap" Margin="218,0,0,0"/>
</Grid>
<Grid Height="30" Margin="8,8,8,0" VerticalAlignment="Top" Grid.Row="2">
<TextBlock Margin="8,0,0,0" Text="AddressLine2" FontSize="16" Foreground="White" HorizontalAlignment="Left" Width="146"/>
<TextBox x:Name="inputAddressLine2" TextWrapping="Wrap" Margin="219,0,0,0"/>
</Grid>
<Grid Height="30" Margin="8,0,8,7" VerticalAlignment="Bottom" Grid.Row="1">
<TextBlock Margin="8,0,0,0" Text="Post Code" FontSize="16" Foreground="White" HorizontalAlignment="Left" Width="107"/>
<TextBox x:Name="inputPostCode" TextWrapping="Wrap" Margin="219,0,0,0"/>
</Grid>
<Grid Height="30" VerticalAlignment="Bottom" Margin="8,0,8,9" Grid.Row="4">
<TextBox x:Name="inputCounty" TextWrapping="Wrap" Margin="220,0,0,0"/>
<TextBlock Margin="8,0,0,0" Text="County" FontSize="16" Foreground="White" HorizontalAlignment="Left" Width="155"/>
</Grid>
<Grid Margin="8,8,8,5" Grid.Row="3">
<TextBox x:Name="inputTown" TextWrapping="Wrap" Margin="219,0,0,0"/>
<TextBlock Margin="8,0,0,0" Text="AddressLine2" FontSize="16" Foreground="White" HorizontalAlignment="Left" Width="165"/>
</Grid>
<Grid Margin="8" Grid.Row="5">
<TextBlock Text="Number" FontSize="16" Foreground="White" Margin="8,0,0,0" HorizontalAlignment="Left" Width="178"/>
<TextBox x:Name="inputNumber" TextWrapping="Wrap" Margin="220,0,0,0"/>
</Grid>
</Grid>
仍然只让它深入一层,返回 6 个网格和一个按钮!
我目前的遍历功能是:
public static IEnumerable<UIElement> Traverse(this UIElementCollection source)
{
source.OfType<Grid>().SelectMany(v => Traverse(v.Children));
//This is the top level.
foreach (UIElement item in source)
{
yield return item;
}
}
这只是知道我们正在处理网格,因此不需要第二个参数。我只是从迭代器框中产生,而不是从应该回调到带有子网格的 Traverse 函数的第一行产生。