我正在尝试使用OLS 实现的predict()
功能。statsmodels.formula.api
当我将新数据框传递给函数以获取样本外数据集的预测值时,result.predict(newdf)
返回以下错误:'DataFrame' object has no attribute 'design_info'
. 这是什么意思,我该如何解决?完整的追溯是:
p = result.predict(newdf)
File "C:\Python27\lib\site-packages\statsmodels\base\model.py", line 878, in predict
exog = dmatrix(self.model.data.orig_exog.design_info.builder,
File "C:\Python27\lib\site-packages\pandas\core\frame.py", line 2088, in __getattr__
(type(self).__name__, name))
AttributeError: 'DataFrame' object has no attribute 'design_info'
编辑:这是一个可重现的例子。当我腌制然后取消腌制结果对象(我需要在我的实际项目中这样做)时,似乎会发生错误:
import cPickle
import pandas as pd
import numpy as np
import statsmodels.formula.api as sm
df = pd.DataFrame({"A": [10,20,30,324,2353], "B": [20, 30, 10, 1, 2332], "C": [0, -30, 120, 11, 2]})
result = sm.ols(formula="A ~ B + C", data=df).fit()
print result.summary()
test1 = result.predict(df) #works
f_myfile = open('resultobject', "wb")
cPickle.dump(result, f_myfile, 2)
f_myfile.close()
print("Result Object Saved")
f_myfile = open('resultobject', "rb")
model = cPickle.load(f_myfile)
test2 = model.predict(df) #produces error