php - 匹配数据库中的名称

Question

我有一张我想在其中匹配的fname表lname

我的查询是

$result = $mysqli->query('SELECT * FROM user_friend_detail WHERE userId = "'.$_SESSION["userId"].'" AND FriendFirstName = "'.mysql_real_escape_string($firstName).'" AND FriendLastName = "'.mysql_real_escape_string($lastName).'"   AND   FriendStatusCode="verified" AND friendId!='.$fid.' ')  or die($mysqli->error);

问题是如果我写Joh'nny,的名字'不匹配，我该如何解决？

Answer 1

由于您已经在使用 mysqli，您不妨使用准备好的语句，这样您就不必担心进行正确的转义：

$stmt = $mysqli->prepare('SELECT * 
    FROM user_friend_detail 
    WHERE userId = ? AND FriendFirstName = ? AND FriendLastName = ?   
      AND   FriendStatusCode="verified" AND friendId <> ?');

$stmt->bind_param('issi', $_SESSION['userId'], $firstName, $lastName, $fid);
$stmt->execute();

也可以看看：mysqli::prepare()

更新

此外，您可能启用了魔术引号，您应该将其关闭。