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很多用户的问题都有谁喜欢这个故事的名字那么我如何按谁投票的已发布链接的数量对用户进行排序。

在 libs/htm1.php 中

function who_voted($storyid, $avatar_size){
// this returns who voted for a story
// eventually add support for filters (only show friends, etc)  
global $db;
if (!is_numeric($storyid)) die();

$sql = 'SELECT ' . table_votes . '.*, ' . table_users . '.* FROM ' . table_votes . ' INNER JOIN ' . table_users . ' ON ' . table_votes . '.vote_user_id = ' . table_users . '.user_id WHERE (((' . table_votes . '.vote_value)>0) AND ((' . table_votes . '.vote_link_id)='.$storyid.') AND (' . table_votes . '.vote_type= "links")) AND user_level<>"god" AND user_level<>"Spammer"';
//echo $sql;
$voters = $db->get_results($sql);
$voters = object_2_array($voters);
foreach($voters as $key => $val){
    $voters[$key]['Avatar_ImgSrc'] = get_avatar($avatar_size, "", $val['user_login'], $val['user_email']);
}

return $voters;

我在 topusers.php 中找到了这些行，但不是为了正确编写函数的友好体验

    case 2: // sort users by number of published links
    $select = "SELECT user_id, count(*) as count ";
    $from_where = " FROM " . table_links . ", " . table_users . " WHERE  link_status = 'published' AND link_author=user_id AND user_level NOT IN ('god','Spammer') AND (user_login!='anonymous' OR user_lastip) GROUP BY link_author";
    $order_by = " ORDER BY count DESC ";
    break;
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0 回答 0