0

我能够将位图插入LruCache但无法检索先前解码的图像。我的数据库中有 100 多张图片。当我对它进行解码时，我的 gc mmemory 正在增加。所以我正在实现它以重用解码后的图像。

protected void onCreate()
{
    LruCache<String, Bitmap> mMemoryCache;
    codeforLru_oncreate();
    aa1=getBitmapFromMemCache(String.valueOf(aa));
    if (aa1 != null) 
    {
      iv.setImageBitmap(aa1);
    } 
    else
    {
      aa1= decodeSampledBitmapFromResource(aa);
      addBitmapToMemoryCache(String.valueOf(aa), aa1);
      iv.setImageBitmap(aa1);
    }
}

获取最大可用 VM 内存，超过此数量将引发 OutOfMemory 异常。以千字节为单位存储，因为 LruCacheint在其构造函数中采用了一个。

public void codeforLru_oncreate() {

    final int maxMemory = (int) (Runtime.getRuntime().maxMemory() / 1024);
    // Use 1/8th of the available memory for this memory cache.
    final int cacheSize = maxMemory / 64;
    mMemoryCache = new LruCache<String, Bitmap>(cacheSize) {
        @Override
        protected int sizeOf(String key, Bitmap bitmap) {
            // The cache size will be measured in kilobytes rather than
            // number of items.
            //app.setFlagForMemoryAlloc(1);
            return bitmap.getByteCount() / 1024;
        }
    };

}
   // code for adding bitmap into cache memory
  public void addBitmapToMemoryCache(String key, Bitmap bitmap) 
    {
    if (getBitmapFromMemCache(key) == null) {

        mMemoryCache.put(key, bitmap);
    }
}



//code for get bitmap from cache memory
public Bitmap getBitmapFromMemCache(String key) {
    return mMemoryCache.get(key);
}

//decoding here......
public Bitmap decodeSampledBitmapFromResource(byte[] decodethis)
{
     return                BitmapFactory.decodeByteArray(decodethis,0,decodethis.length,option);
}
4

0 回答 0