当我在登录屏幕中第二次登录时出现以下错误。
[ERROR ] FWLSE0099E: An error occurred while invoking procedure [project Klappr]KlapprAuthAdapter/submitAuthenticationFWLSE0100E: parameters: [project Klappr]{
"arr": [
"dGVzdDp0ZXN0"
]
}
Cannot change identity of an already logged in user in realm 'KlapprAuthRealm'. The application must logout first.
FWLSE0101E: Caused by: [project Klappr]null
com.worklight.common.log.filters.ErrorFilter
在 submitauthentication(在适配器中)中,我检查用户名和密码是否正确,如果正确,我在 WorklightRealm 中设置 activeUser,如下所示:
WL.Server.setActiveUser("KlapprAuthRealm",{
userId:""+teacher.id,
displayName: teacher.voornaam,
credentials:loginstring,
attributes: {
"teacherId": teacher.id,
}
});
如何检查用户是否已经登录?在我显示登录页面之前,这在客户端是最好的吗?或者我应该让他们能够在其他时间登录,如果他们已经登录,也返回 userId?