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我从 MySQL 收到 1452 错误。这是我用来插入的 SQL

INSERT INTO `Quote` (`QTE_id`, `USR_id`, `QTE_total`, `QTE_desc`, `QTE_dateCreated`, `QTE_dateModified`,`QTE_name`, `QTE_status`)

值（39、2、NULL、'desc'、'2013-11-19 00:00:00'、'2013-11-19 11:22:49'、'test'、'Active'）；

Cannot add or update a child row: a foreign key constraint fails (`dbNAME`.`Quote`, CONSTRAINT `USR_id1` FOREIGN KEY (`USR_id`) REFERENCES `users` (`USR_id`))

我很肯定USR_id我试图放入报价表的存在。有任何想法吗？Stack Overflow 上的许多其他问题都没有回答我的问题。

这是我尝试插入和关联的下表的创建语法（从 Workbench 生成）：

CREATE TABLE `Quote` (
 `QTE_id` int(11) NOT NULL AUTO_INCREMENT,
  `USR_id` int(11) DEFAULT NULL,
  `QTE_total` decimal(7,2) DEFAULT NULL,
  `QTE_desc` text,
  `QTE_dateCreated` timestamp NULL DEFAULT NULL,
  `QTE_dateModified` timestamp NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `QTE_name` varchar(255) DEFAULT NULL,
  `QTE_status` varchar(30) DEFAULT NULL,
   PRIMARY KEY (`QTE_id`),
   KEY `USR_id1` (`USR_id`),
   CONSTRAINT `USR_id1` FOREIGN KEY (`USR_id`) REFERENCES `users` (`USR_id`)
  ) ENGINE=InnoDB AUTO_INCREMENT=39 DEFAULT CHARSET=utf8;

和用户表：

CREATE TABLE `Users` (
 `USR_id` int(11) NOT NULL AUTO_INCREMENT,
  `MGR_id` int(11) NOT NULL DEFAULT '0' 
  `REP_id` int(11) NOT NULL,
  `USR_name` varchar(255) NOT NULL,
  `USR_login` varchar(255) NOT NULL,
  `USR_dateModified` timestamp NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `USR_dateCreated` datetime NOT NULL,
  `USR_role` enum('Salesperson','Manager') DEFAULT NULL,
  PRIMARY KEY (`USR_id`,`MGR_id`,`REP_id`),
  KEY `MGR_id_idx` (`MGR_id`),
  KEY `REP_id_idx` (`REP_id`),
  KEY `USR_login` (`USR_login`),
  CONSTRAINT `MGR_id` FOREIGN KEY (`MGR_id`) REFERENCES `users` (`USR_id`) ON DELETE NO     ACTION ON UPDATE NO ACTION,
  CONSTRAINT `REP_id` FOREIGN KEY (`REP_id`) REFERENCES `representative` (`REP_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
 ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
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1 回答 1

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我必须做一些小的更改（将 更改users为Users，在定义 的行的末尾添加一个 '，' MGR_id，删除对 的约束REP_id）才能使两个 CREATE 工作。

以下是确切的 CREATE：

CREATE TABLE `Users` (
 `USR_id` int(11) NOT NULL AUTO_INCREMENT,
  `MGR_id` int(11) NOT NULL DEFAULT '0',
  `REP_id` int(11) NOT NULL,
  `USR_name` varchar(255) NOT NULL,
  `USR_login` varchar(255) NOT NULL,
  `USR_dateModified` timestamp NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `USR_dateCreated` datetime NOT NULL,
  `USR_role` enum('Salesperson','Manager') DEFAULT NULL,
  PRIMARY KEY (`USR_id`,`MGR_id`,`REP_id`),
  KEY `MGR_id_idx` (`MGR_id`),
  KEY `REP_id_idx` (`REP_id`),
  KEY `USR_login` (`USR_login`),
  CONSTRAINT `MGR_id` FOREIGN KEY (`MGR_id`) REFERENCES `Users` (`USR_id`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION
 ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8;


CREATE TABLE `Quote` (
 `QTE_id` int(11) NOT NULL AUTO_INCREMENT,
  `USR_id` int(11) DEFAULT NULL,
  `QTE_total` decimal(7,2) DEFAULT NULL,
  `QTE_desc` text,
  `QTE_dateCreated` timestamp NULL DEFAULT NULL,
  `QTE_dateModified` timestamp NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE     CURRENT_TIMESTAMP,
  `QTE_name` varchar(255) DEFAULT NULL,
  `QTE_status` varchar(30) DEFAULT NULL,
   PRIMARY KEY (`QTE_id`),
   KEY `USR_id1` (`USR_id`),
   CONSTRAINT `USR_id1` FOREIGN KEY (`USR_id`) REFERENCES `Users` (`USR_id`)
  ) ENGINE=InnoDB AUTO_INCREMENT=39 DEFAULT CHARSET=utf8;

有了它，以下两个 INSERT 工作：

mysql> INSERT INTO `Users` (`USR_id`, `MGR_id`) VALUES(2, 2);
Query OK, 1 row affected, 4 warnings (0.22 sec)

mysql> INSERT INTO `Quote` (`QTE_id`, `USR_id`, `QTE_total`, `QTE_desc`, `QTE_dateCreated`, `QTE_dateModified`,`QTE_name`, `QTE_status`) VALUES (39, 2, NULL, 'desc', '2013-11-19 00:00:00', '2013-11-19 11:22:49', 'test', 'Active');
Query OK, 1 row affected (0.22 sec)

我希望这有帮助。

于 2013-12-11T04:13:15.077 回答