23

我制作了一个 MVC 项目，我想从过滤器中将模型设置为视图。

但我不知道，我该怎么做。

该模型：

public class TestModel
{
    public int ID { get; set; }
    public string Name { get; set; }
}

控制器：

[CustomFilter(View = "../Test/Test")]//<===/Test/Test.cshtml
public ActionResult Test(TestModel testModel)//<===Model from Page
{
      //the Model has Value!!
       // if has some exception here
        return View(model);//<=====/Test/Test.cshtml
}

过滤器（只是演示）：

public override void OnActionExecuting(ActionExecutingContext filterContext){
     ViewResult vr = new System.Web.Mvc.ViewResult()
     {
            ViewName = this.View,//<======/Test/Test.cshtml
            ViewData = filterContext.Controller.ViewData                             
      };
      //How can I set Model here?!!
      vr.Model = ???? //<========the Model is only get
      filterContext.Result = vr;
}

编辑开始感谢@Richard Szalay @Zabavsky @James @spaceman

更改过滤器扩展到 HandleErrorAttribute

  ViewResult vr = new System.Web.Mvc.ViewResult()
     {
            ViewName = this.View,//<======/Test/Test.cshtml
            ViewData = new ViewDataDictionary(filterContext.Controller.ViewData)
            {
                //I want get testModel from Action's paramater
                //the filter extends HandleErrorAttribute
                Model = new { ID = 3, Name = "test" }// set the model
            }                             
      };

编辑结束

测试/Test.chtml

@model TestModel
<h2>Test</h2>
@Model //<=====model is null

当我要求

http://localhost/Test/Test?ID=3&Name=4

测试页无法获取模型。

4

5 回答 5

29 
ViewResult vr = new System.Web.Mvc.ViewResult
    {
        ViewName = this.View, //<======/Test/Test.cshtml
        ViewData = new ViewDataDictionary(filterContext.Controller.ViewData)
            {
                Model = // set the model
            }
    };
于 2013-11-18T08:18:17.623 回答
8

来自 asp.net mvc 源，他们只是在视图数据中设置模型。 http://aspnetwebstack.codeplex.com/SourceControl/latest#src/System.Web.Mvc/Controller.cs

 protected internal virtual ViewResult View(string viewName, string masterName, object model)
    {
        if (model != null)
        {
            ViewData.Model = model;
        }

        return new ViewResult
        {
            ViewName = viewName,
            MasterName = masterName,
            ViewData = ViewData,
            TempData = TempData,
            ViewEngineCollection = ViewEngineCollection
        };
    }
于 2013-11-18T08:20:44.670 回答
5

您可以修改过滤器上下文，并设置视图、模型、视图数据以及您想要的任何内容。你必须考虑一些事情：

// You can specify a model, and some extra info, like ViewBag:
ViewDataDictionary viewData = new ViewDataDictionary
{
    Model = new MyViewModel
    {
        ModelProperty = ...,
        OtherModelProperty = ...,
        ...
    } 
};

// You can take into account if it's a partial or not, to return a View 
// or Partial View (casted to base, to set the remaining data):
ViewResultBase result = filterContext.IsChildAction
    ? new PartialViewResult()
    : (ViewResultBase) (new ViewResult());

// Set the remaining data: Name of the View, (if in Shared folder) or
// Relative path to the view file with extension, like "~/Views/Misc/AView.cshtml"
result.ViewName = View;                     
result.ViewData = viewData;     // as defined above

// Set this as the result
filterContext.Result = result;

这样，您的 View 将根据需要接收模型。

于 2013-12-05T11:10:12.520 回答
3

模型属性实际上只是一个 ViewDataDictionary，您可以使用您的实际模型初始化它的实例，即

vr.Model = new ViewDataDictionary(model);
于 2013-11-18T08:17:56.660 回答
0

您可以从 filtercontext 获取控制器并使用控制器上的 View 方法，如下所示：

filterContext.Result = (filterContext.Controller as Controller).View(model);
于 2019-07-21T21:53:40.303 回答