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我已经成功设置了 Google Maps Store Locator。它运行正常，我使用了 Google 示例中使用的示例 CSV (medicare.csv)：

http://storelocator.googlecode.com/git/examples/panel.html

当我使用来自 Google 的 CSV 文件时它工作正常，但是当我使用我的 CSV 文件（格式相同但列较少）时，无论有多少，它都只会在地图上显示一个结果。我用于测试的那些是：

"Fcilty_nam","Street_add","Locality","State","Postcode","Country","Ycoord","Xcoord","uuid""儿童俱乐部","4530 Union Bay Place Northeast","西雅图","WA","98105","美国","47.6616626","-122.2931334","213" "头肩膝盖和脚趾","12418 102nd Avenue","埃德蒙顿","AB"," T5N 0M1","加拿大","53.5433006","-113.5371704","214"

医疗保险 CSV 的一个例子是：

"Fcilty_typ","State","Fcilty_nam","Shp_num_an","Shp_centre","Street_add","Locality","Postcode","Hrs_of_bus","Wheelchair","Display_wd","Fcilty_typ_2","Xcoord ","Ycoord","uuid","re​​sult","Audio" "MO","NSW","Queanbeyan","Shop 47","Riverside Plaza","131 Monaro Street","Queanbeyan"," 2620","09:00-17:00 周一至周五，公共假期除外","YES","1.5"," http://www.medicareaustralia.gov.au/public/claims/offices.jsp ", "149.23532000","-35.35248400","67","999",""

不幸的是，我无法分享我正在使用的网页，所以我将不得不从代码本身中解决这个问题。我了解我的 CSV 中的列较少，但似乎不需要我未包含的列。有人知道为什么它只会返回一个结果吗？谢谢你的帮助。

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2 回答 2

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我遇到了同样的问题，只要您的 CSV 文件与原始文件格式相同（仅使用文本编辑器，而不是 Excel）：

  • 条目被“引用”
  • 条目以逗号“，”分隔
  • 行尾是“/n”

如果是这样并且您仍然遇到相同的问题，则可能需要切换您的 Xcoord 和 Ycoord...鉴于示例中 CSV 文件的格式，这是一个简单的错误。此外，如果删除列，请注意必须为每个条目拥有唯一的 UUID。

于 2013-11-28T12:32:01.883 回答
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在第一次测试中，您忘记了 . 之间的逗号"uuid" "Kids Club"。让它"uuid", "Kids Club"。在第二次测试中，您忘记了 . 之间的逗号"Audio" "MO"。让它"Audio", "MO"。

于 2013-11-13T00:35:05.650 回答