我在 mac 上制作我的项目,我尝试用 Beagle Bone Black(BBB) 做同样的事情。但是,我无法在 BBB 中使用 urllib,所以我被卡住了:我无法前进。(它在我的 mac 中运行良好)
我以这个简单的代码为例:
导入 urllib conn = urllib.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content')
然后发生此错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib.py", line 86, in urlopen
return opener.open(url)
File "/usr/lib/python2.7/urllib.py", line 207, in open
return getattr(self, name)(url)
File "/usr/lib/python2.7/urllib.py", line 351, in open_http
'got a bad status line', None)
IOError: ('http protocol error', 0, 'got a bad status line', None)
我需要为我的项目获取 html 数据。我怎么解决这个问题?你有什么想法 ?谢谢你。
当我尝试时,urllib2
我得到了这个:
>>> import urllib2
>>> conn = urllib2.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 400, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 418, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib/python2.7/urllib2.py", line 1180, in do_open
r = h.getresponse(buffering=True)
File "/usr/lib/python2.7/httplib.py", line 1030, in getresponse
response.begin()
File "/usr/lib/python2.7/httplib.py", line 407, in begin
version, status, reason = self._read_status()
File "/usr/lib/python2.7/httplib.py", line 371, in _read_status
raise BadStatusLine(line)
httplib.BadStatusLine: ''
我也试过这个:
curl http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content
curl: (52) Empty reply from server
和这个:
wget http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content
Connecting to stackoverflow.com (198.252.206.16:80)
wget: error getting response
但他们没有工作
在家里,我也尝试过但失败了,但返回了一个不同的错误:
conn = urllib2.urlopen('http://stackoverflow.com/questions/8479736/using-python-urllib-how-to-avoid-non-html-content')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 400, in open
response = self._open(req, data)
File "/usr/lib/python2.7/urllib2.py", line 418, in _open
'_open', req)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 1215, in https_open
return self.do_open(httplib.HTTPSConnection, req)
File "/usr/lib/python2.7/urllib2.py", line 1177, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno -2] Name or service not known>
环境
BBB: Linux beaglebone 3.8.13 #1 SMP Tue Jun 18 02:11:09 EDT 2013 armv7l GNU/Linux
python version: 2.7.3