我之前遇到过这个问题并且有很长时间的工作，现在我想在这里发帖。提前致谢！
我正在尝试merge()使用更大的data.frame（不包括）来使用以下小的data.frame（名为HelpData）。下面的代码读取 HelpData，并查看head()和str().
HelpData <- structure(list(`(Intercept)` = c(-0.416714383410771, -0.484420889203111,
0.8852233181836, -0.00573901277840992, 0.819352447999715, -0.0219740206432874,
-0.725659038472068, 0.842129479134587, 0.231330671497113, 1.67161285063258,
0.562139877718068, -0.56702368527195, -1.09763116254353, -0.32410756195596,
0.166964590752782, -0.812461815971089, -0.609301958979508, 0.368263149194526,
0.964304770606394, -0.887610418600415, -0.555998527038864, -0.0940912475713328,
0.706094048452952, -0.500888453405431)), .Names = "(Intercept)", row.names = c("CAL_F01",
"CAL_F17", "CAL_F19", "CAL_F23", "CAL_F43", "CAL_M33", "CAL_M36",
"COL_P01", "COL_P03", "COL_P05", "COL_P06", "COL_P07", "COL_P08",
"COL_P09", "COL_P10", "COL_P12", "COL_P13", "PAT_F02", "PAT_F03",
"PAT_F04", "PAT_F05", "PAT_M02", "PAT_M03", "PAT_M04"), class = "data.frame")
head(HelpData)
str(HelpData)
从str()HelpData 中可以看出，该对象是一个有 24 个 obs 的数据框。1 个变量。“拦截”列是唯一被识别的列。但是我想merge()基于未标记的 AnimalID 字段。下面的代码导致错误
代码：
colnames(HelpData)<- c("CougarID", "RandInt")
错误：
“'names' attribute [2] must be the same length as the vector [1]” This the first coumne is not regonized and thus cannot be named.
更改数据格式的最佳方法是什么，以便我可以拥有相同的两列，但能够命名第一列？
干杯。