c++ - 如何读取名称（仅 file.txt）作为参数传递的文件（在任何目录中）？C++

Question

我想遵循这个架构：

    //Read filename
    string filename; 
cout << "ONLY Name of the file you want to read, not directory: "; 
cin >> filename;

    //Find file in disk C and open it
    ifstream ifs(.................);
    while( int cc = FileRead( ifs, buff ) ) {
       etc. (trivial)
    }

Answer 1

ifstream ifs(filename.c_str());

真的可以用谷歌搜索它......